There is an electric flux of 38.5 N⋅m^2/C through the square region shown in the figure. Each side of the square has a length of 0.100 m, n^ is the unit vector normal to the plane of the surface, and the electric field is at an angle of ?=141 relative to the plane of the surface. Assuming that the field is uniform over the region shown, what is the magnitude ? of the electric field?

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Chapter1: Units, Trigonometry. And Vectors
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There is an electric flux of 38.5 N⋅m^2/C through the square region shown in the figure. Each side of the square has a length of 0.100 m, n^ is the unit vector normal to the plane of the surface, and the electric field is at an angle of ?=141 relative to the plane of the surface.

Assuming that the field is uniform over the region shown, what is the magnitude ? of the electric field?

くミ
ン
Transcribed Image Text:くミ ン
Expert Solution
Step 1

Electric flux through a surface is given by-

ϕE=E.dA=EAcos(θ)

where,
θ is angle between the electric field vector and the area vector.

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