There is a unique group law on the 8- element set Q = {±1, ±i, ±j, ±k} that makes i2 = j2 = k2 = ijk = -1. Right and left multiplication by 1 and -1 are defined as usual. For example, (-1)i = -i = i(-1) and (-1)^2 = 1. (Q is called the quaternion group.) (a) Which of the 8 elements of Q is equal to i^-1? What about -jkj? %3D (b) Compute the orders of all the elements of Q. (c) Provide brief justification for why the subgroup H = {±1}is normal. (d) List a set of distinct coset representatives for Q/H (with H as above). %3D What is the order of each coset in the group Q/H? (e) Compare your answers from parts (b) and (d). Show that Q does not have a subgroup isomorphic to Q/H. Let Q and H be as in the previous question. (a) List all subgroups of Q/H. (b) What subgroups of Q correspond to the subgroups from part (a) under the Correspondence Theorem? (c) Show that every subgroup of Q is normal, even though Q is not abelian.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
Question
I need answer within 5 minutes please please with my best wishes
There is a unique group law on the 8-
element set Q = {±1, ±i, ±j, ±k} that
makes i2 = j2 = k2 = ijk = -1. Right and
left multiplication by
1 and -1 are defined as usual. For
example, (-1)i = -i = i(-1) and (-1)^2 =
1. (Q is called the quaternion group.)
(a) Which of the 8 elements of Q is
equal to i^-1? What about -jkj?
%3D
(b) Compute the orders of all the
elements of Q.
(c) Provide brief justification for why the
subgroup H = {±1}is normal.
(d) List a set of distinct coset
representatives for Q/H (with H as
above).
What is the order of each coset in the
group Q/H?
(e) Compare your answers from parts
(b) and (d). Show that Q does not have
a subgroup isomorphic to Q/H.
Let Q and H be as in the previous
question.
(a) List all subgroups of Q/H.
(b) What subgroups of Q correspond to
the subgroups from part (a)
under the Correspondence Theorem?
(c) Show that every subgroup of Q is
normal, even though Q is not
abelian.
Transcribed Image Text:There is a unique group law on the 8- element set Q = {±1, ±i, ±j, ±k} that makes i2 = j2 = k2 = ijk = -1. Right and left multiplication by 1 and -1 are defined as usual. For example, (-1)i = -i = i(-1) and (-1)^2 = 1. (Q is called the quaternion group.) (a) Which of the 8 elements of Q is equal to i^-1? What about -jkj? %3D (b) Compute the orders of all the elements of Q. (c) Provide brief justification for why the subgroup H = {±1}is normal. (d) List a set of distinct coset representatives for Q/H (with H as above). What is the order of each coset in the group Q/H? (e) Compare your answers from parts (b) and (d). Show that Q does not have a subgroup isomorphic to Q/H. Let Q and H be as in the previous question. (a) List all subgroups of Q/H. (b) What subgroups of Q correspond to the subgroups from part (a) under the Correspondence Theorem? (c) Show that every subgroup of Q is normal, even though Q is not abelian.
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,