Why is the degree wrong? A laboratory exercise on the concept of static equilibriumuses an apparatus called a force table. The force tableconsists of a round, level platform marked in degreeincrements about its circumference. In the center of them,table sits a massless ring, to which three strings are tied.m,Each string is strung over a separate pulley clamped to theedge of the platform and then tied to a freely hangingm,mass, so that each string is under tension and the ring issuspended parallel to the table surface.There is a mass of m = 153 g located at 0, = 26.5° and asecond mass of m2 = 219 g located at 02 = 291°.Calculate the mass m3 and the location 03 (in degrees) thatwill balance the system and hold the ring stationary overthe center of the platform.254.8gm3 =03 =32.3acer

Analyze the following figure, The string’s tension for the given masses can be given as, For m1,…

There is a mass of m = 153 g located at 0, = 26.5° and a second mass of m, = 219 g located at 0, = 291°. Calculate the mass m3 and the location 03 (in degrees) that will balance the system and hold the ring stationary over the center of the platform. 254.8 m3 = 03 = 32.3 50

There is a mass of m = 153 g located at 0, = 26.5° and a second mass of m, = 219 g located at 0, = 291°. Calculate the mass m3 and the location 03 (in degrees) that will balance the system and hold the ring stationary over the center of the platform. 254.8 m3 = 03 = 32.3 50

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter6: Applications Of Newton's Laws

Section: Chapter Questions

Problem 124AP: As shown below, the coefficient of kinetic friction between the surface and the larger block is...

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Why is the degree wrong?

A laboratory exercise on the concept of static equilibrium
uses an apparatus called a force table. The force table
consists of a round, level platform marked in degree
increments about its circumference. In the center of the
m,
table sits a massless ring, to which three strings are tied.
m,
Each string is strung over a separate pulley clamped to the
edge of the platform and then tied to a freely hanging
m,
mass, so that each string is under tension and the ring is
suspended parallel to the table surface.
There is a mass of m = 153 g located at 0, = 26.5° and a
second mass of m2 = 219 g located at 02 = 291°.
Calculate the mass m3 and the location 03 (in degrees) that
will balance the system and hold the ring stationary over
the center of the platform.
254.8
g
m3 =
03 =
32.3
acer

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