There are two toroids that are crossed by the same cable as shown in the figure. Torus A has a mean length twice that of torus B, but its cross section is half. The iron permeability of both toroids is assumed to be identical and constant. The toroids have no air gap. Compare: A). The magnetomotive force (mmf) applied to each of the toroids O (Ctrl) - B) The magnetic fieldH in the each of the toroids C) The flux in each of the toroids So Sa

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Chapter1: Units, Trigonometry. And Vectors
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There are two toroids that are crossed by the same cable as shown in the
figure. Torus A has a mean length twice that of torus B, but its cross
section is half. The iron permeability of both toroids is assumed to be
identical and constant. The toroids have no air gap. Compare:
A). The magnetomotive force (mmf) applied to each of the toroids
竜(Ctrl)
B) The magnetic fieldH in the
each of the toroids
C) The flux in each of the toroids
So
Transcribed Image Text:There are two toroids that are crossed by the same cable as shown in the figure. Torus A has a mean length twice that of torus B, but its cross section is half. The iron permeability of both toroids is assumed to be identical and constant. The toroids have no air gap. Compare: A). The magnetomotive force (mmf) applied to each of the toroids 竜(Ctrl) B) The magnetic fieldH in the each of the toroids C) The flux in each of the toroids So
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