There are two identical, positively charged conducting spheres fixed in space. The spheres are 32.0 cm apart (center to center) and repel each other with an electrostatic force of Fi = 0.0675 N. A thin conducting wire connects the spheres, redistributing the charge on each sphere. When the wire is removed, the spheres still repel, but with a force of F = 0.100 N. The Coulomb force constant is k = 1/(4xe0) = 8.99 x 10° N · m²/C² . Using this information, find the initial charge on each sphere, q and q2, if q, is initially less than q2 . 91 = 92 =

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There are two identical, positively charged conducting spheres fixed in space. The spheres are 32.0 cm apart (center to
center) and repel each other with an electrostatic force of F = 0.0675 N. A thin conducting wire connects the spheres,
redistributing the charge on each sphere. When the wire is removed, the spheres still repel, but with a force of
F = 0.100 N. The Coulomb force constant is k = 1/(4TEO)
= 8.99 × 10° N m²/C2.
Using this information, find the initial charge on each sphere, q and
q2, if q1 is initially less than q2.
92=D
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Transcribed Image Text:There are two identical, positively charged conducting spheres fixed in space. The spheres are 32.0 cm apart (center to center) and repel each other with an electrostatic force of F = 0.0675 N. A thin conducting wire connects the spheres, redistributing the charge on each sphere. When the wire is removed, the spheres still repel, but with a force of F = 0.100 N. The Coulomb force constant is k = 1/(4TEO) = 8.99 × 10° N m²/C2. Using this information, find the initial charge on each sphere, q and q2, if q1 is initially less than q2. 92=D about us careers privacy policy terms of use contact us help
Expert Solution
Step 1

For the initial arrangement, the formula for the electrostatic force between the charged system is:

Physics homework question answer, step 1, image 1

Substitute the known values and solve as:

Physics homework question answer, step 1, image 2

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