There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that plant X is always idling. Event B is that at least two plants generate electricity. Likelihood of the outcomes that Plant X always produce electricity is 44%. If P(AUB)' = 3%, and the likelihood of the outcomes in event A are equally likely, compute the probability of the event B? Solution: P(AUB) = = = P(A) + P(B) − P(AB) - XYZ 000 XYZ 100 010 101 001 110 011 111

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that plant X is always idling.
Event B is that at least two plants generate electricity. Likelihood of the outcomes that Plant X always produce electricity is 44%. If P(AUB)' =3%,
and the likelihood of the outcomes in event. are equally likely, compute the probability of the event B? Solution:
P(AUB) = P(A) + P(B) – P(AB)
XYZ
000
010
001
011
XYZ
100
101
110
111
Transcribed Image Text:There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that plant X is always idling. Event B is that at least two plants generate electricity. Likelihood of the outcomes that Plant X always produce electricity is 44%. If P(AUB)' =3%, and the likelihood of the outcomes in event. are equally likely, compute the probability of the event B? Solution: P(AUB) = P(A) + P(B) – P(AB) XYZ 000 010 001 011 XYZ 100 101 110 111
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