For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Each day can be considered independent of the other days. In the question, What is the probability that Sasha’s first delay due to traffic will occur after the fifth day of work travel? Why is it that the answer is 0.32768? How did we get the solution?
For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Each day can be considered independent of the other days. In the question, What is the probability that Sasha’s first delay due to traffic will occur after the fifth day of work travel? Why is it that the answer is 0.32768? How did we get the solution?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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For each day that Sasha travels to work, the
day can be considered independent of the other days. In the question, What is the probability that Sasha’s first delay due to traffic will occur after the fifth day of work travel? Why is it that the answer is 0.32768? How did we get the solution?

Transcribed Image Text:The probability that Sasha's first traffic delay will occur after the fifth day is the probability that no traffic
delay occurs on any of the first five days:
P(No delay during first 5 days) = (0.8)³ = 0.32768.
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