There are several techniques for implementingthe sqrt method in the Math class. One such technique is known as theBabylonian method. It approximates the square root of a number, n, by repeatedlyperforming the calculation using the following formula:nextGuess = (lastGuess + n / lastGuess) / 2When nextGuess and lastGuess are almost identical, nextGuess is theapproximated square root. The initial guess can be any positive value (e.g., 1).This value will be the starting value for lastGuess. If the difference betweennextGuess and lastGuess is less than a very small number, such as 0.0001,you can claim that nextGuess is the approximated square root of n. If not, nextGuessbecomes lastGuess and the approximation process continues. Implementthe following method that returns the square root of n:public static double sqrt(long n)
There are several techniques for implementing
the sqrt method in the Math class. One such technique is known as the
Babylonian method. It approximates the square root of a number, n, by repeatedly
performing the calculation using the following formula:
nextGuess = (lastGuess + n / lastGuess) / 2
When nextGuess and lastGuess are almost identical, nextGuess is the
approximated square root. The initial guess can be any positive value (e.g., 1).
This value will be the starting value for lastGuess. If the difference between
nextGuess and lastGuess is less than a very small number, such as 0.0001,
you can claim that nextGuess is the approximated square root of n. If not, nextGuess
becomes lastGuess and the approximation process continues. Implement
the following method that returns the square root of n:
public static double sqrt(long n)
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 1 images
