There are 5 different flavors of donuts.  A person may choose either 0 or 1 of each flavor (cannot have more than 1 of a flavor). Person A must choose exactly 2 donuts out of the 5 (can't have 2 of the same donut because of the previously mentioned rule).  Using combinations, we see that 5C2 = 10 different possible combinations.  How would you show the work for the math for this without using combinations and without having to list out all the different personalities?  Trying to understand the simple math (addition or multiplication rules?) Similarly, how would I show the math if other people may choose any combination of the 5 flavors, of how many different possibilities are there?   0 donuts = 1 possibility 1 donut = 5C1 = 5 possibilities 2 donuts = 5C2 = 10 possibilities 3 donuts = 5C3 = 10 possibilities 4 donuts = 5C4 = 5 possibilities 5 donuts = 5C5 = 1 possibility 1 + 5 + 10 + 10 + 5 + 1 = 32 possibilities (how would I do the math for above without using combinations?)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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There are 5 different flavors of donuts. 

A person may choose either 0 or 1 of each flavor (cannot have more than 1 of a flavor).

Person A must choose exactly 2 donuts out of the 5 (can't have 2 of the same donut because of the previously mentioned rule).  Using combinations, we see that 5C2 = 10 different possible combinations.  How would you show the work for the math for this without using combinations and without having to list out all the different personalities?  Trying to understand the simple math (addition or multiplication rules?)

Similarly, how would I show the math if other people may choose any combination of the 5 flavors, of how many different possibilities are there?  

0 donuts = 1 possibility
1 donut = 5C1 = 5 possibilities
2 donuts = 5C2 = 10 possibilities
3 donuts = 5C3 = 10 possibilities
4 donuts = 5C4 = 5 possibilities
5 donuts = 5C5 = 1 possibility

1 + 5 + 10 + 10 + 5 + 1 = 32 possibilities (how would I do the math for above without using combinations?)

Then wanted to double check, if I have to find how many total combinations are there for Person A and "other" people if there are "x" total number of people (i.e. x = 1 means just person A, x = 2 means person A and one "other" person:

10 * 32^(x-1)

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