There are 4 jacks in a standard deck of 52 playing cards. If Patricia selects a card at random, what is the probability that it will be a jack?

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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**Question:**
There are 4 jacks in a standard deck of 52 playing cards. If Patricia selects a card at random, what is the probability that it will be a jack?

**Options:**
- \(\dfrac{1}{52}\)
- \(\dfrac{1}{2}\)
- \(\dfrac{1}{13}\) (Highlighted and selected)
- \(\dfrac{12}{13}\)

**Explanation:**
In a standard deck of 52 playing cards, there are 4 jacks. To find the probability that Patricia selects a jack at random, we can use the formula:

\[ \text{Probability} = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \]

Here, the number of favorable outcomes (selecting a jack) is 4, and the total number of possible outcomes (any card from the deck) is 52. So, the probability is:

\[ \text{Probability} = \dfrac{4}{52} = \dfrac{1}{13} \]

Therefore, the correct answer is \(\dfrac{1}{13}\).

In the image, the correct answer (\(\dfrac{1}{13}\)) is highlighted and selected.
Transcribed Image Text:**Question:** There are 4 jacks in a standard deck of 52 playing cards. If Patricia selects a card at random, what is the probability that it will be a jack? **Options:** - \(\dfrac{1}{52}\) - \(\dfrac{1}{2}\) - \(\dfrac{1}{13}\) (Highlighted and selected) - \(\dfrac{12}{13}\) **Explanation:** In a standard deck of 52 playing cards, there are 4 jacks. To find the probability that Patricia selects a jack at random, we can use the formula: \[ \text{Probability} = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \] Here, the number of favorable outcomes (selecting a jack) is 4, and the total number of possible outcomes (any card from the deck) is 52. So, the probability is: \[ \text{Probability} = \dfrac{4}{52} = \dfrac{1}{13} \] Therefore, the correct answer is \(\dfrac{1}{13}\). In the image, the correct answer (\(\dfrac{1}{13}\)) is highlighted and selected.
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