Then by using "Newton's interpolating polynomial method", the scientist got the following polynomial : p2(x) = 3 +1/2(x−a) + b(x−a)(x−3/2). Now, the scientist wants to do more experiment and got one more point (2,5/3) Therefore, the total data is the following. x 1 3/2 0 2 y 3 13/4 3 5/3 Again by apply Newton's interpolating polynomial method, the scientist obtained the following polynomial p3(x) = c + d(x−1) + (1/3)(x−1)(x−3/2) + e(x−1)(x−3/2)x. Then, answer as an integer or fractional expression (for example, 1/2)
Then by using "Newton's interpolating polynomial method", the scientist got the following polynomial : p2(x) = 3 +1/2(x−a) + b(x−a)(x−3/2). Now, the scientist wants to do more experiment and got one more point (2,5/3) Therefore, the total data is the following. x 1 3/2 0 2 y 3 13/4 3 5/3 Again by apply Newton's interpolating polynomial method, the scientist obtained the following polynomial p3(x) = c + d(x−1) + (1/3)(x−1)(x−3/2) + e(x−1)(x−3/2)x. Then, answer as an integer or fractional expression (for example, 1/2)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
In an experiment, a scientist obtained the following data.
| x | 1 | 3/2 | 0 |
| y | 3 | 13/4 | 3 |
Then by using "Newton's interpolating polynomial method", the scientist got the following polynomial : p2(x) = 3 +1/2(x−a) + b(x−a)(x−3/2).
Now, the scientist wants to do more experiment and got one more point (2,5/3)
Therefore, the total data is the following.
| x | 1 | 3/2 | 0 | 2 |
| y | 3 | 13/4 | 3 | 5/3 |
Again by apply Newton's interpolating polynomial method, the scientist obtained the following polynomial
p3(x) = c + d(x−1) + (1/3)(x−1)(x−3/2) + e(x−1)(x−3/2)x.
Then, answer as an integer or fractional expression (for example, 1/2)
a =
b =
c =
d =
e =
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