Then block resting on the inclined plane shown in the image has a mass of 60 kg. Determine the maximum and minimum value of P for which the block is in equilibrium. (fs= 0.35) P Pmax = Pmin = Block 20° 7777 Newtons (N) - (0 Decimal Places) Newtons (N)-(2 Decimal Places)
Then block resting on the inclined plane shown in the image has a mass of 60 kg. Determine the maximum and minimum value of P for which the block is in equilibrium. (fs= 0.35) P Pmax = Pmin = Block 20° 7777 Newtons (N) - (0 Decimal Places) Newtons (N)-(2 Decimal Places)
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Question 5
Then block resting on the inclined plane shown in the image has a mass of 60 kg.
Determine the maximum and minimum value of P for which the block is in
equilibrium. (fs = 0.35)
P
Pmax =
Pmin =
Block
20°
777
Newtons (N) - (0 Decimal Places)
Newtons (N) (2 Decimal Places)
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