their forms. rest. 11) An insurance company subcontracts two data processing firms to handle Firm #1 handles 80% of the forms and Firm #2 handles the not perfect: it is known that 2% of all forms processed by Firm #1 Unfortunately, these firms are run by people and are therefore will be processed incorrectly and that 5% of those from Firm #2 will also be processed incorrectly. Suppose a random form is chosen from those that have been processed. What is the probability that this form was processed by Firm #2, given that it was processed incorrectly? (Hint: a probability tree or Bayes' Theorem may be

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### Probability and Data Processing: A Case Study of Subcontracted Work

**Problem Statement:**

An insurance company subcontracts two data processing firms to handle their forms. Firm #1 handles 80% of the forms, while Firm #2 handles the rest. Unfortunately, these firms are run by people and are therefore not perfect. Here are some key details:

- It is known that 2% of all forms processed by Firm #1 will be processed incorrectly.
- 5% of the forms from Firm #2 will also be processed incorrectly.

**Question:**

Suppose a random form is chosen from those that have been processed. What is the probability that this form was processed by Firm #2, given that it was processed incorrectly? (Hint: use a probability tree or Bayes' Theorem for the solution.)

**Detailed Explanation:**

When solving this problem, it's helpful to use Bayes' Theorem, which helps us revise existing predictions based on new evidence. Also, we can use a probability tree to visualize the problem.

### Information Recap

- Probability a form is handled by Firm #1: P(F1) = 0.80
- Probability a form is handled by Firm #2: P(F2) = 0.20

- Probability of incorrect processing by Firm #1: P(I|F1) = 0.02
- Probability of incorrect processing by Firm #2: P(I|F2) = 0.05

Our task is to find the probability that a form was handled by Firm #2 given that it was processed incorrectly, i.e., P(F2|I).

### Application of Bayes' Theorem

Bayes' Theorem formula is:

\[ P(F2|I) = \frac{P(I|F2) \cdot P(F2)}{P(I)} \]

Where \( P(I) \) is the total probability of a form being processed incorrectly. This can be calculated by summing the probabilities of incorrect processing from both firms:

\[ P(I) = P(I|F1) \cdot P(F1) + P(I|F2) \cdot P(F2) \]

Substitute the given values:

\[ P(I) = (0.02 \cdot 0.80) + (0.05 \cdot 0.20) \]
\[ P(I) = 0.016 + 0.
Transcribed Image Text:### Probability and Data Processing: A Case Study of Subcontracted Work **Problem Statement:** An insurance company subcontracts two data processing firms to handle their forms. Firm #1 handles 80% of the forms, while Firm #2 handles the rest. Unfortunately, these firms are run by people and are therefore not perfect. Here are some key details: - It is known that 2% of all forms processed by Firm #1 will be processed incorrectly. - 5% of the forms from Firm #2 will also be processed incorrectly. **Question:** Suppose a random form is chosen from those that have been processed. What is the probability that this form was processed by Firm #2, given that it was processed incorrectly? (Hint: use a probability tree or Bayes' Theorem for the solution.) **Detailed Explanation:** When solving this problem, it's helpful to use Bayes' Theorem, which helps us revise existing predictions based on new evidence. Also, we can use a probability tree to visualize the problem. ### Information Recap - Probability a form is handled by Firm #1: P(F1) = 0.80 - Probability a form is handled by Firm #2: P(F2) = 0.20 - Probability of incorrect processing by Firm #1: P(I|F1) = 0.02 - Probability of incorrect processing by Firm #2: P(I|F2) = 0.05 Our task is to find the probability that a form was handled by Firm #2 given that it was processed incorrectly, i.e., P(F2|I). ### Application of Bayes' Theorem Bayes' Theorem formula is: \[ P(F2|I) = \frac{P(I|F2) \cdot P(F2)}{P(I)} \] Where \( P(I) \) is the total probability of a form being processed incorrectly. This can be calculated by summing the probabilities of incorrect processing from both firms: \[ P(I) = P(I|F1) \cdot P(F1) + P(I|F2) \cdot P(F2) \] Substitute the given values: \[ P(I) = (0.02 \cdot 0.80) + (0.05 \cdot 0.20) \] \[ P(I) = 0.016 + 0.
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