The zinc content of a 1.07 g ore sample was determined by dissolving the ore in HCl, which reacts with the zinc. The excess HC1 is then neutralized with with NaOH. The reaction of HCI with Zn is shown. Zn(s) + 2 HCl(aq) → ZnCl₂ (aq) + H₂(g) The ore was dissolved in 150 mL of 0.600 M HCl, and the resulting solution was diluted to a total volume of 300 mL. A 20.0 mL aliquot of the final solution required 9.96 mL of 0.540 M NaOH to neutralize the excess HC1. What is the mass percentage (%w/w) of Zn in the ore sample? %w/w = % Zn
The zinc content of a 1.07 g ore sample was determined by dissolving the ore in HCl, which reacts with the zinc. The excess HC1 is then neutralized with with NaOH. The reaction of HCI with Zn is shown. Zn(s) + 2 HCl(aq) → ZnCl₂ (aq) + H₂(g) The ore was dissolved in 150 mL of 0.600 M HCl, and the resulting solution was diluted to a total volume of 300 mL. A 20.0 mL aliquot of the final solution required 9.96 mL of 0.540 M NaOH to neutralize the excess HC1. What is the mass percentage (%w/w) of Zn in the ore sample? %w/w = % Zn
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:The zinc content of a 1.07 g ore sample was determined by dissolving the ore in HCl, which reacts with the zinc. The excess
HC1 is then neutralized with with NaOH. The reaction of HC1 with Zn is shown.
Zn(s) + 2 HCl(aq) → ZnCl₂ (aq) + H₂(g)
The ore was dissolved in 150 mL of 0.600 M HCl, and the resulting solution was diluted to a total volume of 300 mL. A
20.0 mL aliquot of the final solution required 9.96 mL of 0.540 M NaOH to neutralize the excess HC1. What is the mass
percentage (%w/w) of Zn in the ore sample?
%W/W =
% Zn
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