The Z-transform of the following signal is: (-) 37 a [n] = 6 1 sin %3D 4.73Z-1 1+0.615Z-1 +0.25Z-2 %3D 5.71Z-1 X (3) = %3D 1-0.95Z-1+ 0.25Z-2 -1.85Z-1 X (2) =D= %3D 1 0.951Z-1 +0.25Z-2 2.85Z-1 X (2) 3= %3D 1+0.31Z-1+0.25Z-2
The Z-transform of the following signal is: (-) 37 a [n] = 6 1 sin %3D 4.73Z-1 1+0.615Z-1 +0.25Z-2 %3D 5.71Z-1 X (3) = %3D 1-0.95Z-1+ 0.25Z-2 -1.85Z-1 X (2) =D= %3D 1 0.951Z-1 +0.25Z-2 2.85Z-1 X (2) 3= %3D 1+0.31Z-1+0.25Z-2
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![The Z-transform of the following signal is:
z [n] = 6 ;)
sin
X (x) =
4.73Z-1
1+0.615Z-1 +0.25Z-2
5.71Z-1
X (2) =
1-0.95Z-1+0.25Z-2
-1.85Z-1
%3D
1 0.951Z-1+ 0.25Z-2
2.85Z-1
X (2) =
1+0.31Z-1+ 0.25Z-2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1127a6ae-f493-475e-b31a-e239e843ebbc%2Fef0bbc2e-c0a9-4b8f-b461-936f650c19ea%2F2hk0vy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The Z-transform of the following signal is:
z [n] = 6 ;)
sin
X (x) =
4.73Z-1
1+0.615Z-1 +0.25Z-2
5.71Z-1
X (2) =
1-0.95Z-1+0.25Z-2
-1.85Z-1
%3D
1 0.951Z-1+ 0.25Z-2
2.85Z-1
X (2) =
1+0.31Z-1+ 0.25Z-2
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