How did he get the value inside the circle, can you explain step by step? The above spectoum be written as cam Y(F) = 12.000 S(F +3000) + 12000 S(f-3000) +20000 S(CF+2000+ 20o00 S(F-200) > YE) 24000 SCF-3000) +24000 S(ft300D + 2. 40000 S(F-2000) + yoo00 S(f+2000) 2. ラ YE) - 24000 S(F-3000) + SIf+300) %3D 2 y0000 S(F-200) + S(F+2000) 2 Step 2 of 2:) we know that Ac cos(27Tfct) < Fourier TransFom Ac SCF-fc)+ S(F+F)| APply Inveose TOamsForm to Y(F) we get y (t) = 24000coS (21TX 3000 E) + 40000 COS 2T x 2000t =) yE) = 2400ocos (G000TTE) + 40000 CoS (4000 TE)
How did he get the value inside the circle, can you explain step by step? The above spectoum be written as cam Y(F) = 12.000 S(F +3000) + 12000 S(f-3000) +20000 S(CF+2000+ 20o00 S(F-200) > YE) 24000 SCF-3000) +24000 S(ft300D + 2. 40000 S(F-2000) + yoo00 S(f+2000) 2. ラ YE) - 24000 S(F-3000) + SIf+300) %3D 2 y0000 S(F-200) + S(F+2000) 2 Step 2 of 2:) we know that Ac cos(27Tfct) < Fourier TransFom Ac SCF-fc)+ S(F+F)| APply Inveose TOamsForm to Y(F) we get y (t) = 24000coS (21TX 3000 E) + 40000 COS 2T x 2000t =) yE) = 2400ocos (G000TTE) + 40000 CoS (4000 TE)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:How did he get the value inside
the circle, can you explain step by step?
The above spectoum
be written as
cam
Y(F) =
12000 S(F+3000) + 12000 S(f-3000)+20000 S(CF+200+
20000 8(f-200)
24000 SCF-3000) +24000 S(f+300D) +
2.
y0000 S(f-2000) + yoo00 S(f+2000)
2.
マ YE) -
24000 S(F-3000) + SIf+300)
%3D
2
y0000 S(F-2000) + S(F+2000)
2
Step 2 of 2:)
we
know that
Ac cos(27Tfct) <
Fourier
TransFom Ac SCF-fc)+ S(F+F)|
APply Inve8se TOamsForm to Y(F) we
get
y (t) = 24000cos (21TX 3000 E) + 40000 COS 2T x 2000t
%3D
=) yE) = 2400ocos (G000TTE) + 40000 Cos (400 TE)
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