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The work done by an external force to move a charge from point A to point B is 15x10^4J. If the charge was started from rest and had of kinetic energy 4.82x10 KJ when it reached point B, what must be the potential difference between A and B? How far apart is

The work done by an external force to move a charge from point A to point B is 15x10^4J. If the charge was started from rest and had of kinetic energy 4.82x10 KJ when it reached point B, what must be the potential difference between A and B? How far apart is

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Please take note: Kinetic energy's given is really 4.82 x 10 KJ. Thank you

The work done by an external force to move a charge from point A to point B is 15x10^4J. If the charge was started from rest and had of kinetic energy 4.82x10 KJ when it reached point B, what must be the potential difference between A and B? How far apart is point B from point A?
Transcribed Image Text:The work done by an external force to move a charge from point A to point B is 15x10^4J. If the charge was started from rest and had of kinetic energy 4.82x10 KJ when it reached point B, what must be the potential difference between A and B? How far apart is point B from point A?
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