The width and the cross-sectional area here can be related to depth y by B = 3 + y and Ac = 3y +- Solve for critical depth using: (a) Graphical method (b) Bisection method, using initial guesses of x1 = 0.5 and xµ = 2.5 (c) False position method, using initial guesses of x = 0.5 and xµ = 2.5 Iterate in (b) and (c) till the approximate error falls below 1% or the number of iterations exceeds 10. (d) Discuss your results from (a), (b) and (c).

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The width and the cross-sectional area here can be related to depth y by
y?
B = 3 + y and Ac = 3y +
Solve for critical depth using:
(a) Graphical method
(b) Bisection method, using initial guesses of x = 0.5 and xµ = 2.5
(c) False position method, using initial guesses of x = 0.5 and xu = 2.5
Iterate in (b) and (c) till the approximate error falls below 1% or the number of
iterations exceeds 10.
(d) Discuss your results from (a), (b) and (c).
Transcribed Image Text:The width and the cross-sectional area here can be related to depth y by y? B = 3 + y and Ac = 3y + Solve for critical depth using: (a) Graphical method (b) Bisection method, using initial guesses of x = 0.5 and xµ = 2.5 (c) False position method, using initial guesses of x = 0.5 and xu = 2.5 Iterate in (b) and (c) till the approximate error falls below 1% or the number of iterations exceeds 10. (d) Discuss your results from (a), (b) and (c).
Water is flowing in a trapezoidal channel at a rate of Q = 20 m³/s. The critical depth y for
such a channel must satisfy the equation
Q2
0 = 1- B
where g – 9.81m/s?
Ac – the cross-sectional area (m²)
B - the width of the channel at the surface (m)
Transcribed Image Text:Water is flowing in a trapezoidal channel at a rate of Q = 20 m³/s. The critical depth y for such a channel must satisfy the equation Q2 0 = 1- B where g – 9.81m/s? Ac – the cross-sectional area (m²) B - the width of the channel at the surface (m)
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