Find the minimum and maximum values of the given functions in the indicated region. f(x,y)=x²-3y +y³, x² + 4y² ≤36 a. Min. f(0,-3) = -18, Max. f(± √320,- 1/3) = 986/9 b. Min. f(0, -3) = -18, Max. f(± √320,- 1/3)=986/27 Min. f(0,3)=0, Max. f(+√320,- 1/3)=986/27 Min. f(0, -3) = - 18, Max. f(√320,- 1/3)=986/27 e. Min. f(3,-3)= -9, Max. f(+√320,- 1)=986//27 C. d.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the minimum and maximum values of the given functions in the indicated region.
f(x,y)=x²- 3y +y³, x² +4y² ≤36
Min. f(0, -3) = -18,
Min. f(0, -3)= - 18,
Min. f(0,3)=0,
Max. f(± √320,- 1/3)=986/27
Min. f(0, -3) = -18, Max. f(√320,- 1/3)=986/27
Min. f(3,-3)= -9, Max. f(± √320,- 1) =986//27
a.
b.
C.
d.
e.
Max. f(± √320,- 1/3) =986/9
Max. f(± √320,- 1/3)=986/27
Transcribed Image Text:Find the minimum and maximum values of the given functions in the indicated region. f(x,y)=x²- 3y +y³, x² +4y² ≤36 Min. f(0, -3) = -18, Min. f(0, -3)= - 18, Min. f(0,3)=0, Max. f(± √320,- 1/3)=986/27 Min. f(0, -3) = -18, Max. f(√320,- 1/3)=986/27 Min. f(3,-3)= -9, Max. f(± √320,- 1) =986//27 a. b. C. d. e. Max. f(± √320,- 1/3) =986/9 Max. f(± √320,- 1/3)=986/27
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