The weights of the chocolate in Hershey Kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.1039 g. Is the distribution a standard normal distribution? Why or why not?Is the distribution a standard normal distribution? Why or why not? Choose the correct answer.O A. No, because it has not been converted to a normal distribution yet.O B.Yes, because every normal distribution is also a standard normal distribution. The terms are interchangeable.O C.Yes, because standard normal distributions can have different means and standard deviations.O D. No, because a standard normal distribution has a mean of 0 and a standard deviation of 1C

given data x = weight of chocolate in hershey kisses normal distriburion μ=4.53389 g, σ = 0.1039 g…

Answered: The weights of the chocolate in Hershey…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

What are the two common parameters of normal distribution?
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The scores on a college entrance exam have an approximate normal distribution with mean, μ = 68 points and a standard deviation, σ = 13 points. a. About 68% of the exam scores lie between what two values? These values are: The z-scores are ________________, respectively. About 95% of the exam scores lie between what two values? These values are: The z-scores are________________, respectively. About 99.7% of the exam scores lie between what two values? These values are: The z-scores are ________________, respectively.
To describe a normal distrribution, whicch two of the following are absolutely necesssary? Group of answer choices the standard deviation (or variance) of the distribution the median of the distribution the shape of the distribution the maxmium and minimum of the distribution the mean of the distributionn the size of the distribution
Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose reading from the horse (in mg/100 mg). 92 87 82 107 99 109 85 89 The sample mean x-bar is 93.8. Let x be a random variable representing glucose readings taken from gentle Ben. We may assume x has a normal distribution, and we know from past experience that the standard deviation = 12.5. The mean glucose level for horses should be mu = 85mg/100gl. Do these data indicate that gentle Ben have a overall average glucose level higher than 85? Use alpha = 0.05 A- Compute z value of the sample stasistic test. Round answer to 2 decimal places B- Find (or estimte) the P-Value . Round answer to 4 decimal places I get 1.99 for the z value but cannot come up with correct p-value.
Write YES if the statement is true about the z-distribution and NO if it's not. 1. The z-distribution is a normal distribution witha mean of 0 and standard deviation of 1 2. The normal curve is bell-shaped 3. The tails of a normal curve approach the vertical axis but never touch it.
A normal distribution has a mean of 85.6 and a standard deviation of 4.83. Find the data value corresponding to the value of z given. (Enter your answer to four decimal places.) z = 0.75
Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. The indicated z score is (Round to two decimal places as needed.) ... 0.1867 Z O
Use Table A (Standard Normal Distribution) to find the proportion of observations that satisfies each of the following statements. In each case, shade the area under the curve that is the answer to the question. The table chart below is the one that needs to be looked at to find the proportion of observations that satisfies each of the following statements. The table chart along with the questions that needs to be correctly answered and shaded are below. This deals with Measures of Variations.

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