Choose the statement(s) which is (are) true of a normal distribution. I. it is symmetric about the mean II. the shape of the graph of a normal distribution is mound-shaped III. 99.7% of the data is within 2 standard deviation of the mean o II only OI and II only

Choose the statement(s) which is (are) true of a normal distribution. I. it is symmetric about the mean II. the shape of the graph of a normal distribution is mound-shaped III. 99.7% of the data is within 2 standard deviation of the mean o II only OI and II only

Name: Choose the statement(s) which is (are) true of a normaldistribution.I
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Description: Choose the statement(s) which is (are) true of a normaldistribution.I. it is symmetric about the meanII. the shape of the graph of a normal distribution ismound-shapedIII. 99.7% of the data is within 2 standard deviation ofthe meano II onlyoI and II

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. The area of the shaded region is (Round to four decimal places as needed.) Standard Normal Table (Page 1) NEGATIVE z Scores Z -3.50 and lower -3.4 -3.3 -3.2 -3.1 -3.0 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 -2.2 -2.1 -2.0 -1.9 -1.8 -1.7 -1.6 -1.5 -1.4 -1.3 -1.2 -1.1 -1.0 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 -0.0 Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .0001 .0003 .0005 ,0007 .0010 .0013 .0019 .0026 .0035 .0047 .0062 .0082 .0107 .0139 .0179 .0228 .0287 .0359 0446 0548 .0668 .0808 0968 1151 1357 .1587 1841 2119 .2420 2743 .3085 3446 3821 4207 .4602 .5000 .01 .0003 .0005 .0003 .0005 0007 .0006 .0009 .0009 .0013 .0013 .0018 .0018 .0025 0024 .0034 .0033 0045 0044 0060 .0059 .0080 .0078 0104 .0102 0136 0132 0174…
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Internet Service Providers The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50 and the standard deviation is $20. The distribution is not Normal: many households pay a low rate as part of a bundle with phone or television service, but some pay much more for Internet only or for faster connections. A sample survey asks an SRS of 50 households with Internet access how much they pay. Let x be the mean amount paid. 1. Explain why you can't determine the probability that the amount a randomly selected household pays for access to the Internet exceeds $55. 2. What are the mean and standard deviation of the sampling distribution of x ? 3. What is the shape of the sampling distribution of x ? Justify your answer. 4. Find the probability that the average fee paid by the sample of households exceeds $55.
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What percent of the total population is found between the mean and the z-score given? (Use the standard normal distribution table and enter your answer to two decimal places.) z = 3.56
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4 In an Algebra class, the scores on a test are normally distributed. The middle 68% of the scores fall between 80 and 90. What are the mean and standard deviation for this data?Standard Normal Curve Mean: Standard Deviation:
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