The weights of a certain dog breed are approximately normally distributed with a mean of μ = 51 pounds,and a standard deviation of a = 5 pounds.A dog of this breed weighs 48 pounds. What is the dog's z-score? Round your answer to the nearesthundredth as needed.A dog has a z-score of 0.49. What is the dog's weight? Round your answer to the nearest tenth asneeded.poundsA dog has a z-score of -0.49. What is the dog's weight? Round your answer to the nearest tenth asneeded.Submit Questionpounds

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Answered: The weights of a certain dog breed are…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Scores on an exam were normally distributed. Ten percent of the scores were below 60.0 and 80% were below 81. Find the mean and standard deviation of the scores. (Round the final answer for the mean to two decimal places.) (Round the final answer for the standard deviation to four decimal places.)
IQ scores are normally distributed with a mean of 100 and standard deviation 16. Calculate the z-score for an IQ of 76. Include one decimal place in your answer. Add your answer
Heights for group of people normally distributed with mean = 63 inches and standard deviation = 2.6 inches. Find the height, h such that about 10% of people in the group are shorter than that height. (Round the answer to the nearest tenth.)h = in.What is the percentile, p ranking for that height? p = % You may need to use the appropriate table in the Appendix of Tables to answer this question.
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.481 and standard deviation a = $0.971. E Click the icon to view the frequency distribution for the tax rates. The population mean is S. (Round to three decimal places as needed.) Frequency distribution cigarette tax rates - X The population standard deviation is S (Round to three decimal places as needed.) Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2. 99 3.00-3.49 3.50-399 4.00 4.49 Frequency O Compare these results to the values found using the actual data. 14 O A. The grouped values are both slightly larger. O B. The grouped values are both slightly' smaller. O C. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller. 17 O D. The grouped mean is slightly smaller, while the…
instructor gives a 100-point examination in which the grades are normally distributed. The mean is 66 and the standard deviation is 5. If there are 5% A's and 5% F's, 15% B's and 15% D's, and 60% C's, find the scores that divide the distribution into those categories. Round the cutoff scores to the nearest whole number. Round intermediate z-value calculations to 2 decimal places. A:_- B: C: D: --- F: _-_
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ = $1.638 and standard deviation o = $1.052. Click the icon to view the frequency distribution for the tax rates. The population mean is $ (Round to three decimal places as needed.) book Get more help. C *** Frequency distribution of cigarette tax rates G Search or type URL Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 4.00-4.49 Print Frequency O 7 12 6 6 6 6 3 3 1 Done - X Clear all Check answer
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 70 105 The area of the shaded region is (Round to four decimal places as needed.)
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table C/heights = 5.0 % (Round to the nearest tenth as needed.) Heights Weights CVweights =% (Round to the nearest tenth as needed.) 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
Heights for group of people normally distributed with mean = 65 inches and standard deviation = 2.5 inches. Find the height, h such that about 20% of people in the group are shorter than that height. (Round the answer to the nearest tenth.) h = in. What is the percentile, p ranking for that height?p = %
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)
A normal population has mean u = 50 and standard deviation o = 5. What is the 80th percentile of the population? Use the TI-84 Plus calculator. Round the answer to at least one decimal place.

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