Heights for group of people normally distributed with mean = 63 inches and standard deviation 2.9 inches.ЛUSE SALTFind the height, h such that about 20% of people in the group are shorter than that height. (Round the answer to the nearest tenth.)h =✓ in.What is the percentile, p ranking for that height?p =× %

The objective of this question is to find the height that corresponds to the 20th percentile of a…

Answered: Heights for group of people normally…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the histogram. Complete the table. Round values to the nearest tenth as needed. Graph/chart f Midpoint x xf 70.5 Ay 30- 92.5 26 25- 114.5 136.5 20- 158.5 15- 12 Ef = Exf = 10- Find the mean of the data set. 5- X = (Round to the nearest tenth as needed.) 48.5 70.5 92.5 114.5 136.5 158.5 Complete the table. Round values to the nearest tenth as needed. Midpoint x (x-x)? (x-x)?f X-X 70.5 Print Done 92.5 114.5 136.5 158.5 (x-x)?r= ] of
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The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ = $1.638 and standard deviation o = $1.052. Click the icon to view the frequency distribution for the tax rates. The population mean is $ (Round to three decimal places as needed.) book Get more help. C *** Frequency distribution of cigarette tax rates G Search or type URL Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 4.00-4.49 Print Frequency O 7 12 6 6 6 6 3 3 1 Done - X Clear all Check answer
Use the dot plots to find the mean, median, and IQR of each class. Round to 1 deccimal place, if needed. 3. 2. 4. Class A 8. 10 10 Class B mean median IQR Class A Class B
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table C/heights = 5.0 % (Round to the nearest tenth as needed.) Heights Weights CVweights =% (Round to the nearest tenth as needed.) 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
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Find the mean and median from the frequency table below.If necessary, round your answer to 2 decimal places. data frequency 29 4 30 5 32 2 35 3 36 16 Mean= Median=
Use the data in the following table, which lists carbon dioxide concentrations (in parts per million) for each year from 1960 to 2009, with projected values used for the last four years. After finding the values of the mean and range for each decade, find the values of x, and R. Also find the values of LCL and UCL for an R chart, and find the values of LCL and UCL for an x chart. 1960s 318.4 319.5 321.8 322.9 324.8 325.4 326.9 328.5 330.3 331.4 1970s 333.4 334.6 335.5 337.1 339.3 340.4 341.4 343.1 344.7 346.5 1980s 348.1 348.8 351.2 352.1 353.8 355.4 356.9 358.5 359.8 360.6 1990s 361.9 363.6 365.8 366.7 368.6 369.2 371.7 372.4 373.5 375.2 2000s 377.6 378.7 379.6 381.8 382.8 384.2 386.3 387.6 388.7 390.5 x=enter your response here (Round to three decimal places as needed.) Part 2 R=enter your response here (Round to two decimal places as needed.) Compute the values of LCL and UCL for an R chart. LCL=enter your response here, UCL=enter your response here (Round to…
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