Asap c. Compare the conclusions reached in (a) and (b). Choose the correct answer below.O A. The confidence interval and hypothesis test both show that there is sufficient evidence to support the claim that the mean difference is not equal to D.D Inches.OB. The confidence interval shows sufficient evidence while the hypothesis test shows insufficient evidence to support the claim that the mean difference is not equal to 0.0 inches.OC. The confidence interval shows insufficient evidence while the hypothesis test shows sufficient evidence to support the claim that the mean difference is not equal to 0.0 inches.OD. The confidence interval and hypothesis test both show that there is insufficient evidence to support the claim that the mean difference is not equal to 0.0 inches.d. Because n-80, do you have to be concerned about the normality assumption needed for the t test and t interval?OA. With the large sample size, the t test is still valid unless the population is very skewed.O B. Yes, because the population distribution must be normal for all sample sizes.OC. Yes, because the normality assumption is needed if the hypothesis test shows sufficient evidence that the mean difference is not equal to 0.0 inches.O D. No, because the normality assumption is needed only if the hypothesis test shows sufficient evidence that the mean difference is not equal to 0.0 Inches.Differences dataDifference between actual length and specified length Full data set Q0.0030 0.0010 0.0025 0.0025 0.0030 0.0030 0.0010 0.0000-0.0025 0.0000 0.0005 -0.0015 -0.0005 0.00200.0005 -0.0025-0.0030 -0.0025 -0.0025 -0.0030 -0.0030 -0.0025 -0.0005 0.00150.0005 -0.0015 -0.0015 0.0005 0.0015 0.0005 -0.0030 -0.00300.0020 -0.0030 0.0020 -0.0025 0.0005 0.0020 0.0015 0.0005-0.0010 0.0015 0.0025 0.00050.0015 -0.0030 -0.0010 0.0015-0.0015 0.0005 -0.0020 -0.0015 -0.0020 0.0030 0.0025-0.0030 -0.0025 0.0030 -0.0015 -0.0010 0.0020 0.0025 0.00100.0010 0.0015 0.0010 0.0005 0.0030 0.0030 0.0010 -0.00300.0010 0.0020 0.0005 0.0020 -0.0015 0.00250.00250.00150.0010 The data for a sample of 80 steel parts, given in the accompanying table, show the reported difference, in inches, between the actual length of the steel part and the specified length of the steel part.For example, a value of -0.002 represents a steel part that is 0.002 inch shorter than the specified length. Complete parts (a) through (d).Click the icon to view the data table.a. At the 0.10 level of significance, is there evidence that the mean difference is different from 0.0 inches?State the null and alternative hypotheses.HotH₁: p▼Determine the test statistic.tSTAT =(Round to two decimal places as needed.)Find the p-value.p-value= (Round to three decimal places as needed.)State the conclusion.Ho. There isb. Construct a 90% confidence interval estimate of the population mean.Sμs(Round to six decimal places as needed.)evidence to conclude that the mean difference is not equal to 0.0 inches.

Given is the differences b/w actual and specified length of 80 steel parts. α=0.10 H0: μ=0 H1: μ≠0

a. At the 0.10 level of significance, is there evidence that the mean difference is different from 0.0 inches? State the null and alternative hypotheses. Hai H₁: H Determine the test statistic. ISTAT = (Round to two decimal places as needed.) Find the p-value. p-value = (Round to three decimal places as needed.) State the conclusion. Ho. There is b. Construct a 90% confidence interval estimate of the population mean. ☐sμs (Round to six decimal places as needed) evidence to conclude that the mean difference is not equal to 0.0 inches.

a. At the 0.10 level of significance, is there evidence that the mean difference is different from 0.0 inches? State the null and alternative hypotheses. Hai H₁: H Determine the test statistic. ISTAT = (Round to two decimal places as needed.) Find the p-value. p-value = (Round to three decimal places as needed.) State the conclusion. Ho. There is b. Construct a 90% confidence interval estimate of the population mean. ☐sμs (Round to six decimal places as needed) evidence to conclude that the mean difference is not equal to 0.0 inches.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Asap

c. Compare the conclusions reached in (a) and (b). Choose the correct answer below.
O A. The confidence interval and hypothesis test both show that there is sufficient evidence to support the claim that the mean difference is not equal to D.D Inches.
OB. The confidence interval shows sufficient evidence while the hypothesis test shows insufficient evidence to support the claim that the mean difference is not equal to 0.0 inches.
OC. The confidence interval shows insufficient evidence while the hypothesis test shows sufficient evidence to support the claim that the mean difference is not equal to 0.0 inches.
OD. The confidence interval and hypothesis test both show that there is insufficient evidence to support the claim that the mean difference is not equal to 0.0 inches.
d. Because n-80, do you have to be concerned about the normality assumption needed for the t test and t interval?
OA. With the large sample size, the t test is still valid unless the population is very skewed.
O B. Yes, because the population distribution must be normal for all sample sizes.
OC. Yes, because the normality assumption is needed if the hypothesis test shows sufficient evidence that the mean difference is not equal to 0.0 inches.
O D. No, because the normality assumption is needed only if the hypothesis test shows sufficient evidence that the mean difference is not equal to 0.0 Inches.
Differences data
Difference between actual length and specified length Full data set Q
0.0030 0.0010 0.0025 0.0025 0.0030 0.0030 0.0010 0.0000
-0.0025 0.0000 0.0005 -0.0015 -0.0005 0.00200.0005 -0.0025
-0.0030 -0.0025 -0.0025 -0.0030 -0.0030 -0.0025 -0.0005 0.0015
0.0005 -0.0015 -0.0015 0.0005 0.0015 0.0005 -0.0030 -0.0030
0.0020 -0.0030 0.0020 -0.0025 0.0005 0.0020 0.0015 0.0005
-0.0010 0.0015 0.0025 0.0005
0.0015 -0.0030 -0.0010 0.0015
-0.0015 0.0005 -0.0020 -0.0015 -0.0020 0.0030 0.0025
-0.0030 -0.0025 0.0030 -0.0015 -0.0010 0.0020 0.0025 0.0010
0.0010 0.0015 0.0010 0.0005 0.0030 0.0030 0.0010 -0.0030
0.0010 0.0020 0.0005 0.0020 -0.0015 0.0025
0.0025
0.0015
0.0010

The data for a sample of 80 steel parts, given in the accompanying table, show the reported difference, in inches, between the actual length of the steel part and the specified length of the steel part.
For example, a value of -0.002 represents a steel part that is 0.002 inch shorter than the specified length. Complete parts (a) through (d).
Click the icon to view the data table.
a. At the 0.10 level of significance, is there evidence that the mean difference is different from 0.0 inches?
State the null and alternative hypotheses.
Hot
H₁: p
▼
Determine the test statistic.
tSTAT =
(Round to two decimal places as needed.)
Find the p-value.
p-value= (Round to three decimal places as needed.)
State the conclusion.
Ho. There is
b. Construct a 90% confidence interval estimate of the population mean.
Sμs
(Round to six decimal places as needed.)
evidence to conclude that the mean difference is not equal to 0.0 inches.

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