The weights of a certain brand of candies are normally distributed with a mean weight of 0.8557 g and a standard deviation of 0.0521 g. A sample of these candies came from a package containing 446 candies, and the package label stated that the net weight is 380.8 g. (If every package has 446 candies, the mean weight of the candies must exceed 380.8/446 = 0.8539 g for the net contents to weigh at least 380.8 g.)
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The weights of a certain brand of candies are
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- The weights of a certain brand of candies are normally distributed with a mean of0.8588g and a standard deviation of 0.0524 g. A sample of these candies came from a package containing 462 candies, and the packaging label stated that the net weight is 394.2 g. (if every package has 462 candies, the mean weight of the candies must exceed 394.2/ 462=0.8532g for the net contents to weigh at least 394.2g.) If a candy is randomly selected, what is the probability that it weighs more than 0.8532g?In a sample of 14 randomly selected high school seniors, the mean score on a standardized test was 1197 and the standard deviation was 166.9. Further research suggests that the population mean score on this test for high school seniors is 1018. Does the t-value for the original sample fall between -to.95 and to.95? Assume that the population of test scores for high school seniors is normally distributed. fall between -to.95 and to.95 because to.95 = The t-value of t= (Round to two decimal places as needed.) CA certain grade egg must weigh at least 2.0 Oz. If the weights of eggs are normally distributed with a mean of 1.5oz. And a standard deviation of 0.4oz, approximately how many eggs would you expect to weigh more than 2oz?
- The brain volumes (cm3) of 20 brains have a mean of 1138.1 cm3 and a standard deviation of 120.4 cm3. Use the given standard deviation and the range rule of thumb to identify the limits separating values that are signigicantly low or significantly high. For such data, would a brain volume of 1388.9 cm3 be significantly high?The weights of 1,000 men in a certain town follow a normal distribution with a mean of 150 pounds and a standard deviation of 15 pounds. From the data, we can conclude that the number of men weighing more than 165 pounds is about , and the number of men weighing less than 135 pounds is about .The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.34°F and a standard deviation of 0.56°F. Using the empirical rule, find each approximate percentage below. a. What is the approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.22°F and 99.46°F? b. What is the approximate percentage of healthy adults with body temperatures between 97.78°F and 98.90°F? a. Approximately % of healthy adults in this group have body temperatures within 2 standard deviations of the mean, or between 97.22°F and 99.46°F. (Type an integer or a decimal. Do not round.)
- For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 33 beats per minute, the mean of the listed pulse rates is x =74.0 beats per minute, and their standard deviation iss = 13.2 beats per minute. a. What is the difference between the pulse rate of 33 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 33 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 33 beats per minute significant? a. The difference is beats per minute. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal as needed.) c. The z score is z= (Round to two decimal places as needed.) d. The lowest pulse rate isThe distribution of the student heights at a large college is approximately bell shaped. If the mean height is 66 inches,and approximately 95% of the heights fall between 32 and 100 inches, then, the standard deviation of the heightdistribution is approximately equal toThe board of examiners that administers the real estate broker’s examination in a certain state found that the mean score on the test was 450 and the standard deviation was 50. If the board wants to set the passing scores so that only the top 5% of all applicants pass, what should the passing score be? Assume that the scores are normally distributed.
- Suppose that the mean cranial capacity for men is 1190 cc (cubic centimeters) and that the standard deviation is 300 cc. Assuming that men's cranial capacities are normally distributed, complete the following statements. (a) Approximately 99.7% of men have cranial capacities between I cc and cc. (b) Approximately ? of men have cranial capacities between 590 cc and 1790 cc.A population of normally distributed data has a mean of 200 and a stabdard deviation of 20. Assuming that all observations are integers, what is the least value that belongs to the uppee 10% of the distribution?A parenting magazine reports that the average amount of wireless data used by teenagers each month is 5 Gb. For her science fair project, Ella sets out to prove the magazine wrong. She claims that the mean among teenagers in her area is less than reported. Ella collects information from a simple random sample of 25 teenagers at her high school, and calculates a mean of 4.7 Gb per month with a standard deviation of 0.9 Gb per month. Assume that the population distribution is approximately normal. Test Ella's claim at the 0.01 level of significance. Step 3 of 3: Draw a conclusion and interpret the decision. E Tables E Keypad Answer Keyboard Shortcuts We reject the null hypothesis and conclude that there is sufficient evidence at a 0.01 level of significance that the average amount of wireless data used by teenagers each month is less than 5 Gb. We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 0.01 level of significance that the average amount of…