The weight of a loaf of bakery bread at the grocery store follows a Normal distribution with a mean of µ = 12 ounces and a standard deviation of σ = 1 ounce. Suppose we pick four loaves at random from the bin andfind their total weight, W. Which of the following statements describes the random variable W?O The random variable W is binomial, with a mean of 48 ounces and a standard deviation of two ounces.O The random variable W is binomial, with a mean of 12 ounces and a standard deviation of two ounces.O The random variable W is Normal, with a mean of 12 ounces and a standard deviation of one ounce.O The random variable W is Normal, with a mean of 48 ounces and a standard deviation of two ounces.O The random variable W is Normal, with a mean of 48 ounces and a standard deviation of four ounces.

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Answered: The weight of a loaf of bakery bread at…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that a vending machine dispenses coffee in amounts that vary uniformly between 7.5 and 12.5 ounces per cup. Calculate the mean and variance of the distribution. Select one: O a. 12.5 and 5 O b. 10 and 2.08 c. 10 and 3.8 O d. 12.5 and 2.08
The plasticity of a polyethylene is affected by the concentration of a solution. When low concentration of the solution is used, the true mean plasticity is 55. And when high concentration is used, the mean plasticity is 62. The standard deviation of plasticity is 4 regardless of concentration of the solution. If two random samples of size 18 are taken, find the probability that Xhigh – X low 2 5. Include your solutions. O a. Probability is about 98% O b. Probability is about 7% O. NONE O d. Probability is about 93%
Assume that the time it takes the housekeeping crew of a local hotel to clean a room varies uniformly between 25 and 50 minutes. Calculate the mean and variance for the distribution. Select one: O a. 37.5 and 50.08 O b. 15.5 and 50.08 O c. 51.2 and 36.6 O d. 37.5 and 78.5
The average cost per household of owning a brand new car is $5,500. Suppose that we randomly selected 45 households, determine the probability that the sample mean for these 45 households is between $5,250 and 6,000. Assume that the variable is normally distributed and the standard deviation is $1,550. SD of the sample mean (input 4 decimal places)= type your answer... type your answer... z-scores (input 2 decimal places) type your answer... Final answer/Probability (input 2 decimal places type your answer... %
the heights of 18-year old men are approximately normally distributed with a mean of U= 68 inches and a standard deviation of O=3. what is the probability that an 18-year-old mean selected at random is less than 65 inches tall. a .8413 b .1587 c .1389 d .8765
Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose readings from this horse (in mg/100 ml). 93 87 81 103 101 111 83 89 The sample mean is x = 93.5. Let x be a random variable representing glucose eadings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that o = 12.5. The mean glucose level for horses should be u = 85 mg/100 ml.t Do these data indicate hat Gentle Ben has an overall average glucose level higher than 85? Use = 0.05. (a) What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right- tailed, or two-tailed test? O Ho: H = 85; H1: µ 85; right-tailed O Ho: H > 85; H1: µ = 85; right-tailed O Ho: H = 85; H1: µ ± 85; two-tailed (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. O The Student's t, since we assume that x has a normal distribution with…
The probability that a radish seed will germinate is 0.7. A gardener plants seeds in batches of 9. Find the standard deviation for the binomial random variable X, the number of seeds germinating in each batch Round to three decimals A. 1.375. OB. 1.296 O C. 1.281 OD. 1.358
Scores of each of the Knitting Aptitude tests were normally distributed with a mean of 6 hours and a standard deviation of 1.67 hours. Carrie will be taking the test tomorrow. Assume the data is normally distributed. Determine the probability of someone finishing in less than 2.17 hours 0.9891 0.5000 1.0 0.0109
The general philosophy of standardizing is that standardizing a random variable involves a. Subtracting the main in the batting by the standard deviation b. Dividing the standard deviation of the total of successes by the total of trials c. Adding and subtracting standard deviations in each direction d. Subtracting the area in the right tail from 1 since the Z chart gives only the area "to the left"
The full height of a certain species of tree has a normal probability distribution with a mean of 195.6 ft and a standard deviation of 7.5 ft. State the random variable. ¯x = the height of a certain species of tree ¯x = the mean height of a certain species of tree x = the height of a certain species of tree x = the diameter of a certain species of tree A tree of this type grows in my backyard, and it stands 187.4 feet tall. Find the probability that the height of a randomly selected tree is shorter than mine. Round to three decimal places.Which is the notation for the probability that the height is shorter than mine? P(x < 187.4) P(¯x < 195.6) P(¯x > 195.6) P(x > 195.6) P(¯x< 187.4) P(x < 195.6)
The weights of large eggs are normally distributed with mean 65 grams and standard deviation 4 grams. The weights of standard eggs are normally distributed with mean 50 grams and standard deviation 3 grams. 1. One large egg and one standard egg are chosen at random. Find the probability that the weight of the standard egg is more than 4/5 of the weight of the large egg. 2. Standard eggs are sold in packs of 12 while large eggs are sold in packs of 5. Find the probability that the weight of a pack of standard eggs differs from twice the weight of a pack of large eggs by at most 5 grams. This is Probability and Statistics

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