The weight distribution of parcels sent in a certain manner is normal with mean value 16 Ib and standard deviation 3.4 lb. The parcel service wishes to establish a weightvalue c beyond which there will be a surcharge.n USE SALTWhat value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight? (Round your answer to four decimal places.)C =Ib

Answered: The weight distribution of parcels sent…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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SHOW COMPLETE SOLUTIONS. EXPRESS FINAL ANSWERS IN 3 DECIMAL PLACES. PLEASE ANSWER NUMBER 4 AND 5 QUESTION.
Use the output provided in the formula sheets folder. Using the reduced model, what is the value of S (standard deviation)? O 0.80 O 2.85 O 57 O 221.2
Neighborhood of House Std. Deviation Mean Std. Error 48 $468,082.77 $19,665.822 $136,248.811 1353.022 Staten Selling Price of House 195.292 Living Space of House in Square Feet Island 48 1961.81 Dungan Hills Lot Size of Land around 48 3785.67 242.833 1682.394 House in Square Feet Price per Square Foot of 48 $483.04 $202.362 $1,402.007 House 30 $522,433.33 $29,744.861 $162,919.312 142.659 Selling Price of House Staten 781.376 Living Space of House in Square Feet Lot Size of Land around 30 1907.33 Island Sunrise 4549.00 391.338 2143.447 House in Square Feet Price per Square Foot of 30 $290.30 $12.604 $69.033 House Machine Claims Quiz Descriptive Statistics and Test of Hypothesis John Jimland is the manager of a manufacturing facility that produces small machinery. While the machines are expected to function normally, occasional, malfunctions lead to claims for damaged goods. There are different types of claims: Claims due to corrosion, wiring, or malfunction. John would like to explain…
Length of snowboards in a boardshop are normally distributed with a mean of 150.4 cm and a standard deviation of 0.7 cm. The figure below shows the distribution of the length of snowboards in a boardshop. Calculate the shaded area under the curve. Express your answer in decimal form with at least two decimal place accuracy. 149.7 151.8 The Length of Snowboards in a Boardshop
The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the SD of the measurements is 20 mm. The histogram looks reasonably like a normal curv Use the normal curve to estimate the following percentages. Choose the answer that is closest to being correct. A 19.1% B 30.9% C 38.2% D 69.1% E 68.27% A The percentage of people with blood pressure between 130 and 150 mm. B The percentage of people with blood pressure between 140 and 150 mm. D The percentage of people with blood pressure over 150 mm.
Page 2 of 5 B. Organizing and Working with Data. 1. Find the z-score for the weight of a 155-pound woman. The mean weight of woman age 20 or older is 170.6 pounds with a standard deviation of 5.4 pounds. Round your answer to two decimal places.
3. Find the standard deviation of X. A. 2.77 B. 2.79 C. 2.81 D. 2.83 E. 2.85
suppose that peices of a gallon of mill at various stores in one town have amean of $3.75 with a stabdard deviation of $0.09 use chebyshev theourm what is the minimum percentage of stires that sell a gallon of milk for between $3.57 and $3.93 round your answer tk ine decimal place
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is less than 0.89 and draw a sketch of the region. Sketch the region. Choose the correct graph below. O A. -0.89 The probability is (Round to four decimal places as needed.) B. -0.89 0.89 C. A -0.89 D. 0.89
Prices of diamonds are determined by what is known as the 4 Cs: cut, clarity, color, and carat weight. The prices of diamonds go up as the carat weight increases, but the increase is not smooth. For example, the difference between the size of a 0.99 carat diamond and a 1 carat diamond is undetectable to the naked human eye, but the price of a 1 carat diamond tends to be much higher than the price of a 0.99 carat diamond. In this question we use two random samples of diamonds, 0.99 carat and 1 carat, each sample of size 23, and compare the average prices of the diamonds. In order to be able to compare equivalent units, we first divide the price for each diamond by 100 times its weight in carats. That is, for a 0.99 carat diamond, we divide the price by 99. For a 1 carat diamond, we divide the price by 100. The distributions and some sample statistics are shown below. 80 60 40 20 0.99 carats 1 carat 0.99 carats 1 carat Mean $42.51 $56.83 SD $12.31 $16.12 n 23 23 Point price (in dollars)

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