The walls of a refrigerator are typically constructed by sandwiching a layer of insulation between sheet metal panels. Consider a wall made from fiberglass insulation of thermal conductivity k, = 0.046 W/m.K and thickness L, = 50 mm and steel panels, each of thermal conductivity k, = 60 W/m.K and thickness L, = 3 mm. If the wall separates refrigerated air at Ť = 4 C from ambient air at T, 25 C, what is the heat gain per unit surface area? Coefficients associated with natural convection at the inner and outer surfaces may be approximated as h; = h. = 5 W/m?.K. %3D %3D Lj = 0.050 m- Lp = 0.003 m Refrigerated air Ambient air Too,i = 4°C h; = 5 W/m2-K To,o ho = 5 W/m2-K = 25°C %3D Panel (2) Insulation k; = 0.046 W/m-K q" ko = 60 W/m-K
The walls of a refrigerator are typically constructed by sandwiching a layer of insulation between sheet metal panels. Consider a wall made from fiberglass insulation of thermal conductivity k, = 0.046 W/m.K and thickness L, = 50 mm and steel panels, each of thermal conductivity k, = 60 W/m.K and thickness L, = 3 mm. If the wall separates refrigerated air at Ť = 4 C from ambient air at T, 25 C, what is the heat gain per unit surface area? Coefficients associated with natural convection at the inner and outer surfaces may be approximated as h; = h. = 5 W/m?.K. %3D %3D Lj = 0.050 m- Lp = 0.003 m Refrigerated air Ambient air Too,i = 4°C h; = 5 W/m2-K To,o ho = 5 W/m2-K = 25°C %3D Panel (2) Insulation k; = 0.046 W/m-K q" ko = 60 W/m-K
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
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![Homework
O H.W. 1:
The walls of a refrigerator are typically constructed by sandwiching a layer of
insulation between sheet metal panels. Consider a wall made from fiberglass
insulation of thermal conductivity k; = 0.046 W/m.K and thickness L, = 50 mm
and steel panels, each of thermal conductivity k, = 60 W/m.K and thickness L,
= 3 mm. If the wall separates refrigerated air at T = 4 C from ambient air at T,.
= 25 C, what is the heat gain per unit surface area? Coefficients associated
with natural convection at the inner and outer surfaces may be approximated
as h, = h, = 5 W/m?.K.
%3D
%3D
L; = 0.050 m K
K Lo = 0.003 m
Refrigerated
air
Ambient air
Too.i = 4°C
hi = 5 W/m2-K
To,o = 25°C
ho = 5 W/m2-K
%3D
Panel (2)
kp = 60 W/m-K
Insulation
k; = 0.046 W/m-K
22
Warith Alanbiyaa (Dr. ALI M)
Heat Transfer
Page 11 of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3827ab1-7dcf-4cd2-894f-efa2ee587599%2F08d304fc-a101-4fbf-b9bf-e4b0d113b8f2%2Fbe9f6i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Homework
O H.W. 1:
The walls of a refrigerator are typically constructed by sandwiching a layer of
insulation between sheet metal panels. Consider a wall made from fiberglass
insulation of thermal conductivity k; = 0.046 W/m.K and thickness L, = 50 mm
and steel panels, each of thermal conductivity k, = 60 W/m.K and thickness L,
= 3 mm. If the wall separates refrigerated air at T = 4 C from ambient air at T,.
= 25 C, what is the heat gain per unit surface area? Coefficients associated
with natural convection at the inner and outer surfaces may be approximated
as h, = h, = 5 W/m?.K.
%3D
%3D
L; = 0.050 m K
K Lo = 0.003 m
Refrigerated
air
Ambient air
Too.i = 4°C
hi = 5 W/m2-K
To,o = 25°C
ho = 5 W/m2-K
%3D
Panel (2)
kp = 60 W/m-K
Insulation
k; = 0.046 W/m-K
22
Warith Alanbiyaa (Dr. ALI M)
Heat Transfer
Page 11 of
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