The W= 5 kN/m uniformly distributed loaded composite steel beam is shown in Figure (a). The steel composite section consists of two steel plates, each with dimensions of 228 x 10mm and a universal beam section Section3 (See Table 1) are bolted together to form the composite section as shown in Figure (b). The 16 mm diameter bolts are spaced longitudinally every 150 mm. The sectional properties are given in Figure (c) and Table 1. The modulus of elasticity for steel is 200 GPa. a w kN/m 10 m- Figure (a) Simply supported beam Steel plate UB Section (c) UB Section Steel plate (b) Section a-a (dimensions not to scale) Figure (b) Section a-a & (c) UB section Table 1. Sectional properties UB Section A mm? lae. (x10° mm) lyo (x10° mm) 39 3 br Section mm mm mm mm 1 610UB125 16000 612 229 19.6 11.9 986 2 610UB113 14500 607 228 17.3 11.2 875 34.3 3 610UB101 13000 602 533 228 14.8 10.6 761 29.3 4 530UB92.4 11800 209 15.6 10.2 554 23.8 5 530UB82 10500 528 209 13.2 |9.6 477 20.1
The W= 5 kN/m uniformly distributed loaded composite steel beam is shown in Figure (a). The steel composite section consists of two steel plates, each with dimensions of 228 x 10mm and a universal beam section Section3 (See Table 1) are bolted together to form the composite section as shown in Figure (b). The 16 mm diameter bolts are spaced longitudinally every 150 mm. The sectional properties are given in Figure (c) and Table 1. The modulus of elasticity for steel is 200 GPa. a w kN/m 10 m- Figure (a) Simply supported beam Steel plate UB Section (c) UB Section Steel plate (b) Section a-a (dimensions not to scale) Figure (b) Section a-a & (c) UB section Table 1. Sectional properties UB Section A mm? lae. (x10° mm) lyo (x10° mm) 39 3 br Section mm mm mm mm 1 610UB125 16000 612 229 19.6 11.9 986 2 610UB113 14500 607 228 17.3 11.2 875 34.3 3 610UB101 13000 602 533 228 14.8 10.6 761 29.3 4 530UB92.4 11800 209 15.6 10.2 554 23.8 5 530UB82 10500 528 209 13.2 |9.6 477 20.1
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![The W= 5 kN/m uniformly distributed loaded composite steel beam is shown in Figure (a). The steel composite section consists of two steel plates, each
with dimensions of 228 x 10mm and a universal beam section Section3 (See Table 1) are bolted together to form the composite section as shown in
Figure (b). The 16 mm diameter bolts are spaced longitudinally every 150 mm. The sectional properties are given in Figure (c) and Table 1. The modulus
of elasticity for steel is 200 GPa.
a
w kN/m
10 m-
Figure (a) Simply supported beam
Steel plate
UB Section
(c) UB Section
Steel plate
(b) Section a-a (dimensions not to scale)
Figure (b) Section a-a & (c) UB section
Table 1. Sectional properties
UB Section
A
mm?
lae.
(x10° mm)
lyo
(x10° mm)
39 3
br
Section
mm
mm
mm
mm
1
610UB125
16000
612
229
19.6 11.9
986
2
610UB113
14500
607
228
17.3 11.2
875
34.3
3
610UB101
13000
602
533
228
14.8 10.6
761
29.3
4
530UB92.4
11800
209
15.6
10.2
554
23.8
5
530UB82
10500
528
209
13.2 |9.6
477
20.1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F53ce1657-b18a-4e5a-99aa-3e87bdade9e3%2Fbb05a98e-6968-49e2-8f58-3c69a7ae12d4%2Fy51ril8_processed.png&w=3840&q=75)
Transcribed Image Text:The W= 5 kN/m uniformly distributed loaded composite steel beam is shown in Figure (a). The steel composite section consists of two steel plates, each
with dimensions of 228 x 10mm and a universal beam section Section3 (See Table 1) are bolted together to form the composite section as shown in
Figure (b). The 16 mm diameter bolts are spaced longitudinally every 150 mm. The sectional properties are given in Figure (c) and Table 1. The modulus
of elasticity for steel is 200 GPa.
a
w kN/m
10 m-
Figure (a) Simply supported beam
Steel plate
UB Section
(c) UB Section
Steel plate
(b) Section a-a (dimensions not to scale)
Figure (b) Section a-a & (c) UB section
Table 1. Sectional properties
UB Section
A
mm?
lae.
(x10° mm)
lyo
(x10° mm)
39 3
br
Section
mm
mm
mm
mm
1
610UB125
16000
612
229
19.6 11.9
986
2
610UB113
14500
607
228
17.3 11.2
875
34.3
3
610UB101
13000
602
533
228
14.8 10.6
761
29.3
4
530UB92.4
11800
209
15.6
10.2
554
23.8
5
530UB82
10500
528
209
13.2 |9.6
477
20.1
![a)
Calculate the maximum bending moment and shear force;
Mmax =
kNm
Vmax =
kN
Submit part
Unanswered
b)
Determine the location of the centroid with respect to the point P;
y =
mm
Submit part
Unanswered
c)
Determine the moment of inertia lx with respect to the centroidal axes.
x106 mm*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F53ce1657-b18a-4e5a-99aa-3e87bdade9e3%2Fbb05a98e-6968-49e2-8f58-3c69a7ae12d4%2Feuxni9e_processed.png&w=3840&q=75)
Transcribed Image Text:a)
Calculate the maximum bending moment and shear force;
Mmax =
kNm
Vmax =
kN
Submit part
Unanswered
b)
Determine the location of the centroid with respect to the point P;
y =
mm
Submit part
Unanswered
c)
Determine the moment of inertia lx with respect to the centroidal axes.
x106 mm*
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