The volume of 1.5 kg of hydorgen in a piston-cylinder device is initially 6 m. Now hydrogen is compressed to 2.5 m while its pressure is maintained constant at 190 kPa.Considering hydrogen as an ideal gas, determine 1) the initial temperature (T1). final temperature (T)) of hydrogen and the work required (Wh in) to compress the gas, in kJ. (See Table A-1 for value of R of hydrogen) Tq= 230.36 K. T2= 92.14 K, Wb in = 570 kJ C T1= 184 29 K. T2 = 76.79 K, Wb in = 665 kJ. T1 = 161 25 K 2 = 69 11 K. Wh in = 760 kJ Oc. T1 = 147 43 K T2 = 64.5 K. WNy in = 855 kJ

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The volume of 1.5 kg of hydorgen in a piston-cylinder device is initially 6 m. Now hydrogen is compressed to 2.5 m' while its pressure is maintained
constant at 190 kPa.Considering hydrogen as an ideal gas, determine
1) the initial temperature (T), final temperature (T2) of hydrogen and the work required (Wh in) to compress the gas, in kJ.
(See Table A-1 for value of R of hydrogen)
T1= 230.36 K, T2 = 92.14 K, Wp in = 570 kJ
Oa.
T1= 184.29 K. T2 = 76.79 K, Wb in = 665 kJ.
T1= 161 25 K. T2 = 69 11 K. Wb in = 760 kJ
Tq = 147 43 K. T2 = 64.5 K. Wh in = 855 kJ
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Transcribed Image Text:The volume of 1.5 kg of hydorgen in a piston-cylinder device is initially 6 m. Now hydrogen is compressed to 2.5 m' while its pressure is maintained constant at 190 kPa.Considering hydrogen as an ideal gas, determine 1) the initial temperature (T), final temperature (T2) of hydrogen and the work required (Wh in) to compress the gas, in kJ. (See Table A-1 for value of R of hydrogen) T1= 230.36 K, T2 = 92.14 K, Wp in = 570 kJ Oa. T1= 184.29 K. T2 = 76.79 K, Wb in = 665 kJ. T1= 161 25 K. T2 = 69 11 K. Wb in = 760 kJ Tq = 147 43 K. T2 = 64.5 K. Wh in = 855 kJ « < Question 7 of 8 > » A Moving to another question will save this response ceull lis isI 4) G O D A PrtSc Insert Delete *- F11 F12 F9 F10 F6 F7 F8 F4 F5 F2 F3 Backspan & 24
The temperature of an ideal gas changes during a throttling.
True
False
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Transcribed Image Text:The temperature of an ideal gas changes during a throttling. True False A Moving to another question will save this response.
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