The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR, to find how the current I is changing at the moment when R = 362 , I = 0.08 A, dv/dt = -0.07 V/s, and dR/dt = 0.01 /s. (Round your answer to six decimal places.) A/s

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