If a cup of coffee has temperature 91°C in a room where the ambient air temperature is 25 according to Newton's Law of Cooling, the temperature of the coffee after t minutes is T(t) = 25+66e-1/55. What is the average temperature of the coffee during the first 16 m average temp =
If a cup of coffee has temperature 91°C in a room where the ambient air temperature is 25 according to Newton's Law of Cooling, the temperature of the coffee after t minutes is T(t) = 25+66e-1/55. What is the average temperature of the coffee during the first 16 m average temp =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![If a cup of coffee has a temperature of 91°C in a room where the ambient air temperature is 25°C, then, according to Newton's Law of Cooling, the temperature of the coffee after \( t \) minutes is
\[ T(t) = 25 + 66e^{-t/55} \]
What is the average temperature of the coffee during the first 16 minutes?
\[ \text{average temp} = \boxed{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }°C \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ea1f414-2cfa-4d12-9b16-9c9fcbba0754%2Fa9dce8f6-b936-44c1-b69d-fe10230d2c6a%2F2nytaaf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If a cup of coffee has a temperature of 91°C in a room where the ambient air temperature is 25°C, then, according to Newton's Law of Cooling, the temperature of the coffee after \( t \) minutes is
\[ T(t) = 25 + 66e^{-t/55} \]
What is the average temperature of the coffee during the first 16 minutes?
\[ \text{average temp} = \boxed{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }°C \]
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