The voltage pulse shown in is applied to the ideal integrating amplifier shown in and v. (0) = 0. Vg (mv) 200 0 -200 250 25 kn 500 5 MO w 400 nF HE 6 V -6V 1 (ms)

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The voltage pulse shown in
is applied to the ideal
integrating amplifier shown
in and v. (0) = 0.
Vg (mv)
200
0
-200
4
250
25 kn
ww
1=0
500
5 MO
w
400 nF
HE
6V
-6V
1 (ms)
Transcribed Image Text:The voltage pulse shown in is applied to the ideal integrating amplifier shown in and v. (0) = 0. Vg (mv) 200 0 -200 4 250 25 kn ww 1=0 500 5 MO w 400 nF HE 6V -6V 1 (ms)
Part A
Derive the numerical expression for u.(t) for the time interval t < 0.
Express your answer in terms of t, where t is in seconds.
vo(t)
=
Part B
V
Derive the numerical expression for u(t) for the time interval 0 ≤t≤ 250 ms.
Ovo(t)=200(1-e 100) V
Ovo(t)=40(1e-100) V
Ovo(t) 200(1-e-05) V
Ovo(t)=40(1-e 0.5t) V
Transcribed Image Text:Part A Derive the numerical expression for u.(t) for the time interval t < 0. Express your answer in terms of t, where t is in seconds. vo(t) = Part B V Derive the numerical expression for u(t) for the time interval 0 ≤t≤ 250 ms. Ovo(t)=200(1-e 100) V Ovo(t)=40(1e-100) V Ovo(t) 200(1-e-05) V Ovo(t)=40(1-e 0.5t) V
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