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A BJT amplifier circuit shown to the right. Vcc=10V, I=1mA, and VT 25 mV at 300K. e) de voltage Vc = f) gm = g) r₂ = h) re= = R₁ 15K 4K Cs W- Re R₂ 10K Re 5K 8=99 BAZAART

A BJT amplifier circuit shown to the right. Vcc=10V, I=1mA, and VT 25 mV at 300K. e) de voltage Vc = f) gm = g) r₂ = h) re= = R₁ 15K 4K Cs W- Re R₂ 10K Re 5K 8=99 BAZAART

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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### BJT Amplifier Circuit Analysis **Description:** A BJT amplifier circuit is shown with a supply voltage \( V_{CC} = 10V \), a current \( I = 1mA \), and a thermal voltage \( V_T = 25mV \) at 300K. **Circuit Diagram:** - **Transistor Configuration:** - The transistor is a Bipolar Junction Transistor with a current gain (\( \beta \)) of 99. - Terminals are labeled as Emitter (E), Base (B), and Collector (C). - **Components:** - \( R_1 = 15k\Omega \) and \( R_2 = 10k\Omega \) form the voltage divider bias network. - \( R_C = 5k\Omega \) is the collector resistor. - \( R_L = 5k\Omega \) is the load resistor. - \( R_S = 4k\Omega \) represents the source resistor. - \( C_S \) and \( C_C \) are coupling capacitors, with the assumption that they act as shorts for AC signals. - The voltage source is labeled as \( V_S \), and the output voltage is \( v_o \). **Required Calculations:** - **(e)** DC Voltage at the collector, \( V_C = \_\_\_\_\_\_\_\_ \) - **(f)** Transconductance, \( g_m = \_\_\_\_\_\_\_\_ \) - **(g)** Input resistance at the base, \( r_{\pi} = \_\_\_\_\_\_\_\_ \) - **(h)** Emitter resistance, \( r_e = \_\_\_\_\_\_\_\_ \) This content is intended for educational purposes, providing insights into the analysis and operational characteristics of a BJT amplifier circuit.
Transcribed Image Text:### BJT Amplifier Circuit Analysis **Description:** A BJT amplifier circuit is shown with a supply voltage \( V_{CC} = 10V \), a current \( I = 1mA \), and a thermal voltage \( V_T = 25mV \) at 300K. **Circuit Diagram:** - **Transistor Configuration:** - The transistor is a Bipolar Junction Transistor with a current gain (\( \beta \)) of 99. - Terminals are labeled as Emitter (E), Base (B), and Collector (C). - **Components:** - \( R_1 = 15k\Omega \) and \( R_2 = 10k\Omega \) form the voltage divider bias network. - \( R_C = 5k\Omega \) is the collector resistor. - \( R_L = 5k\Omega \) is the load resistor. - \( R_S = 4k\Omega \) represents the source resistor. - \( C_S \) and \( C_C \) are coupling capacitors, with the assumption that they act as shorts for AC signals. - The voltage source is labeled as \( V_S \), and the output voltage is \( v_o \). **Required Calculations:** - **(e)** DC Voltage at the collector, \( V_C = \_\_\_\_\_\_\_\_ \) - **(f)** Transconductance, \( g_m = \_\_\_\_\_\_\_\_ \) - **(g)** Input resistance at the base, \( r_{\pi} = \_\_\_\_\_\_\_\_ \) - **(h)** Emitter resistance, \( r_e = \_\_\_\_\_\_\_\_ \) This content is intended for educational purposes, providing insights into the analysis and operational characteristics of a BJT amplifier circuit.
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