The voltage of a received signal is assumed to be normally distributed with standard deviation 0.16 volt. The receiver tests Ho : u = 2 volt, against H : 4# 2 volt, using n = 12. Let the acceptance region be 1.8 s S 2.2. (1) find the value of a. (2) Find Bif the true mean output is 2.1 volt. (3) Find the power of the test for detecting a true mean output 2.1 volt.

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The voltage of a received signal is assumed to be normally distributed with standard deviation 0.16 volt. The receiver tests
Ho: u = 2 volt, against H: H # 2 volt, using n = 12.
Let the acceptance region be 1.8 SES 2.2.
(1) find the value of a.
(2) Find B if the true mean output is 2.1 volt.
(3) Find the power of the test for detecting a true mean output 2.1 volt.
O a. (1)a = 0.617, 6 = 0.3721, Power 0.2747
O b. (1)a = 0.617, B = 0.1721, Power = 0.1747
%3D
O c. (1)a = 0.417, ß = 0.3721, Power = 0.1747
Od. (1)a = 0.617.p = 0.3721, Power = 0.1747
Transcribed Image Text:The voltage of a received signal is assumed to be normally distributed with standard deviation 0.16 volt. The receiver tests Ho: u = 2 volt, against H: H # 2 volt, using n = 12. Let the acceptance region be 1.8 SES 2.2. (1) find the value of a. (2) Find B if the true mean output is 2.1 volt. (3) Find the power of the test for detecting a true mean output 2.1 volt. O a. (1)a = 0.617, 6 = 0.3721, Power 0.2747 O b. (1)a = 0.617, B = 0.1721, Power = 0.1747 %3D O c. (1)a = 0.417, ß = 0.3721, Power = 0.1747 Od. (1)a = 0.617.p = 0.3721, Power = 0.1747
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