The voltage differences (∆ε) for the following two half reactions are: Cu2+ + e- → Cu+          ∆ε = +0.34 V Fe3+ + e- → Fe 2+         ∆ε = +0.77 V In one aqueous solution, the concentrations of Cu2+, Cu+, Fe3+ and Fe 2+ are all 1 mol/L. Which of them acts as an oxidant

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