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The voltage differences (∆ε) for the following two half reactions are: Cu2+ + e- → Cu+          ∆ε = +0.34 V Fe3+ + e- → Fe 2+         ∆ε = +0.77 V In one aqueous solution, the concentrations of Cu2+, Cu+, Fe3+ and Fe 2+ are all 1 mol/L. Which of them acts as an oxidant

The voltage differences (∆ε) for the following two half reactions are: Cu2+ + e- → Cu+          ∆ε = +0.34 V Fe3+ + e- → Fe 2+         ∆ε = +0.77 V In one aqueous solution, the concentrations of Cu2+, Cu+, Fe3+ and Fe 2+ are all 1 mol/L. Which of them acts as an oxidant

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The voltage differences (∆ε) for the following two half reactions are:

Cu2+ + e- → Cu+          ∆ε = +0.34 V

Fe3+ + e- → Fe 2+         ∆ε = +0.77 V

In one aqueous solution, the concentrations of Cu2+, Cu+, Fe3+ and Fe 2+ are all 1 mol/L. Which of them acts as an oxidant?


 

a.

 

Fe 2+


 

b.

 

Cu+


 

c.

 

Fe3+


 

d.

 

Cu2+

 

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