The voltage across a 200 mH inductor is v(t) = (1 – 3t)e¬3tmV. Find the current flowing through the inductor. Assume i (0) = 0. %3D

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**Problem 7: Inductor Current Calculation**

The problem involves a 200 mH inductor with a given voltage across it as:

\[ v(t) = (1 - 3t)e^{-3t} \, \text{mV} \]

The task is to find the current flowing through the inductor. It is given that the initial current is:

\[ i(0) = 0 \]

**Explanation:**

1. **Voltage Across an Inductor**: The voltage \( v(t) \) across an inductor is related to the current \( i(t) \) through the differential equation:
   \[
   v(t) = L \frac{di(t)}{dt}
   \]
   where \( L \) is the inductance of the inductor.

2. **Inductance Value**: Here, \( L = 200 \, \text{mH} = 0.2 \, \text{H} \).

3. **Initial Condition**: The initial current through the inductor is zero, \( i(0) = 0 \).

To find the current \( i(t) \), one would typically integrate the expression after rearranging the differential equation.
Transcribed Image Text:**Problem 7: Inductor Current Calculation** The problem involves a 200 mH inductor with a given voltage across it as: \[ v(t) = (1 - 3t)e^{-3t} \, \text{mV} \] The task is to find the current flowing through the inductor. It is given that the initial current is: \[ i(0) = 0 \] **Explanation:** 1. **Voltage Across an Inductor**: The voltage \( v(t) \) across an inductor is related to the current \( i(t) \) through the differential equation: \[ v(t) = L \frac{di(t)}{dt} \] where \( L \) is the inductance of the inductor. 2. **Inductance Value**: Here, \( L = 200 \, \text{mH} = 0.2 \, \text{H} \). 3. **Initial Condition**: The initial current through the inductor is zero, \( i(0) = 0 \). To find the current \( i(t) \), one would typically integrate the expression after rearranging the differential equation.
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