**Velocity-Time Graph Analysis**The diagram above displays a velocity versus time graph for an object, where:- The horizontal axis represents time \( t \) in seconds.- The vertical axis represents velocity \( v(t) \).Points on the graph:- **A** to **B**: The graph shows a linear decrease in velocity, indicating negative acceleration.- **B** to **C**: The velocity increases linearly, indicating positive acceleration.- **C** to **D**: The velocity remains constant, meaning the acceleration is zero.- **D** to **E**: The velocity increases again, indicating positive acceleration.### Questions(a) **Direction of Acceleration**Determine the direction of the acceleration of the object for each of the indicated time intervals:- **A to B**: *Negative direction*- **B to C**: *Positive direction*- **C to D**: *Acceleration is zero*- **D to E**: *Positive direction*(b) **Direction of Net Force**Identify the direction of the net force acting on the object for each of the indicated time intervals:- **A to B**: *Select the appropriate direction*- **B to C**: *Positive direction*- **C to D**: *The net force is zero*- **D to E**: *Positive direction***Note:** The net force direction is aligned with the acceleration due to Newton's second law of motion.

The slope of the curve in velocity versus time graph gives the measure of the acceleration.

The velocity versus time graph for an object is shown in the diagram below. v (t) --Select-- positive direction B (a) What is the direction of the acceleration of the object for each of the indicated time intervals? A to B negative direction B to C positive direction C to D the acceleration is zero D to E positive direction negative direction D (b) What is the direction of the net force acting on the object for each of the indicated time intervals? A to B --Select--- B to C C to D D to E the net force is zero E t (s)

The velocity versus time graph for an object is shown in the diagram below. v (t) --Select-- positive direction B (a) What is the direction of the acceleration of the object for each of the indicated time intervals? A to B negative direction B to C positive direction C to D the acceleration is zero D to E positive direction negative direction D (b) What is the direction of the net force acting on the object for each of the indicated time intervals? A to B --Select--- B to C C to D D to E the net force is zero E t (s)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

Question

**Velocity-Time Graph Analysis**

The diagram above displays a velocity versus time graph for an object, where:

- The horizontal axis represents time \( t \) in seconds.
- The vertical axis represents velocity \( v(t) \).

Points on the graph:

- **A** to **B**: The graph shows a linear decrease in velocity, indicating negative acceleration.
- **B** to **C**: The velocity increases linearly, indicating positive acceleration.
- **C** to **D**: The velocity remains constant, meaning the acceleration is zero.
- **D** to **E**: The velocity increases again, indicating positive acceleration.

### Questions

(a) **Direction of Acceleration**

Determine the direction of the acceleration of the object for each of the indicated time intervals:

- **A to B**: *Negative direction*
- **B to C**: *Positive direction*
- **C to D**: *Acceleration is zero*
- **D to E**: *Positive direction*

(b) **Direction of Net Force**

Identify the direction of the net force acting on the object for each of the indicated time intervals:

- **A to B**: *Select the appropriate direction*
- **B to C**: *Positive direction*
- **C to D**: *The net force is zero*
- **D to E**: *Positive direction*

**Note:** The net force direction is aligned with the acceleration due to Newton's second law of motion.

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