The velocity vector, v(t) of a particle in motion is given by v(t)=t√t² +4i+e²j+ -k. 2t+1 Find: (i) the position vector, r(t) if given the initial position is r(0)=3i-j+2k. the acceleration vector, a (t).

The motion of a point on the circumference of a rolling wheel of radius 5 feet is described by the vector function r(t) = Find the velocity vector of the point. v(t) = = 5(13t – sin(13t))i + 5(1 = Find the acceleration vector of the point. a(t) Find the speed of the point. s(t) = 65√2- 2 cos (13t) = - cos(13t))j Add Work

At time t = 0, a particle is located at the point (5,9,4). It travels in a straight line to the point (2,1,3), has speed 5 at (5,9,4) and constant acceleration - 3i-8j - k. Find an equation for the position vector r(t) of the particle at time t. The equation for the position vector r(t) of the particle at time t is r(t) = (Type exact answers, using radicals as needed.) i+ j+ k.