The motion of a point on the circumference of a rolling wheel of radius 5 feet is described by the vector function r(t) = Find the velocity vector of the point. v(t) = = 5(13t – sin(13t))i + 5(1 = Find the acceleration vector of the point. a(t) Find the speed of the point. s(t) = 65√2- 2 cos (13t) = - cos(13t))j Add Work

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