The velocity of a stone thrown upward with a velocity of 12.0 m/s in a medium that has resistance is given by the differential equation dv = (-9.81 m/s²) – (1.00/s) v dt before it reaches the ground. At what time after it was thrown will it reach its maximum height? Answer: seconds (3 decimal

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Chapter1: Units, Trigonometry. And Vectors
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Applications of the first-order Differential Equations
The velocity of a stone thrown upward with a
velocity of 12.0 m/s in a medium that has
resistance is given by the differential equation
dv
(-9.81 m/s²) – (1.00/s) v
dt
before it reaches the ground. At what time
after it was thrown will it reach its maximum
height?
Answer:
seconds (3 decimal
places)
Transcribed Image Text:The velocity of a stone thrown upward with a velocity of 12.0 m/s in a medium that has resistance is given by the differential equation dv (-9.81 m/s²) – (1.00/s) v dt before it reaches the ground. At what time after it was thrown will it reach its maximum height? Answer: seconds (3 decimal places)
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