The velocity of a particle moving in the x-y plane is given by (5.92i + 4.07j) m/s at time t = 5.92 s. Its average acceleration during the next 0.019 s is (2.2i + 3.2j) m/s². Determine the velocity v of the particle at t = 5.939 s and the angle between the average- acceleration vector and the velocity vector at t = 5.939 s. Answers: V = ( i 0 = i i+ i j) m/s

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A: For solution refer below images.

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A: The velocity at  is The velocity at  is

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A: To be found out:-Direction of acceleration at t=0.5 s

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A: Given Data⇒Radius =600 metersincrease in speed =0.15 ms2speed of car =17msProblem definition⇒Problem…

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A: Given data:

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Fluid Kinematics

The branch of science that deals with objects which are either in motion or stationary are studied under the branch of classical mechanics. Fluid mechanics is a subcategory of classical mechanics that deals with the behavior of fluids at rest (fluid statics) or in motion (posing some velocity). In fluid kinematics, studies focus on the associated motion of fluid particles or groups of particles, and its associated parameters like displacements, velocity, and acceleration without concerning about the forces that caused the motion. All the laws of classical mechanics are applied in the study of fluid kinematics.