The velocity of a particle (m = 10 mg, q = - 4.0 µC) at t 0 is 20 m/s in the positive x-direction. If the particle moves in a uniform electric field of 20 N/C in the positive x-direction, what is the particle's velocity ( in m/s) at t = 8.7 s?
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- An electron is moving with a velocity, v = (0.000i, 6.95x10²j, 0.00k)m/s, when it enters a region of uniform electric field E=(6.40i, 0.00j, 0.00k) N/C. mẹ = 9.11x10-3!kg, qe= -1.60x10-1ºC a. What is the acceleration of the electron while it is in the region with the electric field? b. How far has the electron moved in the z direction after traveling 5.00cm in the +y direction?A particle of charge q=3.0 uC and mass m=2.0 mg enters a region of a uniform electric field as shown in the figure, with vj = 3.00 x 10° m/s, E = 222 N/C, and b = 0.100 m. Find the magnitude of the acceleration (in m/s2) of the particle while it is in the electric field. (0, 0) 07:48P 31°CA proton has a mass of about 1.673x10-27kg. If an electron is placed in a region of space within which a constant electric field exists with magnitude 4.156 N/C, how long would it take this proton to travel a distance of 649.72m in units of ms (milliseconds)? Assume the proton does not collide with anything along the way. Hint: You will need to use the kinematic relationships for linear motion that we learned back in PHY 2010. This results of this problem show you that small charges like protons, and electrons too, move great distances in a short amount of time under very small external electric fields - if those charges are in a vacuum - otherwise, they quickly strike a nearby charge.
- A proton has a mass of about 1.673x10-27kg. If an electron is placed in a region of space within which a constant electric field exists with magnitude 4.878 N/C, how long would it take this proton to travel a distance of 218.64m in units of ms (milliseconds)? Assume the proton does not collide with anything along the way. Hint: You will need to use the kinematic relationships for linear motion that we learned back in PHY 2010. This results of this problem show you that small charges like protons, and electrons too, move great distances in a short amount of time under very small external electric fields - if those charges are in a vacuum - otherwise, they quickly strike a nearby charge. Note: It is understood that the unit of your answer is in milliseconds, however do not explicitly include units in your answer. Enter only a number.What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 8651 N/C and is directed due north?An electron is initially moving horizontally at v0 = 3x10-6 m/s when it enters a uniform electric field of 5.6 N/C directed virtually down. What are the horizontal and vertical components of its velocity 2 μs after entering the electric field?
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