A particle of mass m = 1.0 mg and charge 2.0 µC is placed in a region of space that has a constant electric field of magnitude 2000 N/C. What is the magnitude of the acceleration of the particle? 1 m/s? O 4 m/s? O 9.8 m/s? O 2000 m/s? O 4000 m/s? O 4x 10° m/s?
Q: The velocity of a particle (m = 10 mg, q = - 4.0 µC) at t = 0 is 20 m/s in the positive x-direction.…
A: Answer:20m/s Options are incorrect.
Q: At some instant the velocity components of an electron moving between two charged parallel plates…
A: The horizontal component of the velocity, vx=1.6×105 m/s The vertical component of the velocity,…
Q: An electric field with a magnitude of 6.0 x 104 N/C is directed parallel to the positive y axis. A…
A:
Q: Write an expression for the magnitude of the electric field due to the charge distribution on the…
A:
Q: An electron enters a region of uniform electric field with an initial velocity of 49 km/s in the…
A: Initial velocity (u) = 49 km/sElectric field magnitude (E) = 54 N/CTime (t) = 1.4 ns
Q: An electron with speed 2.60x107 m/s is traveling parallel to a uniform electric field of magnitude…
A:
Q: An electron initially at rest is released in a uniform electric field, and the electron is…
A:
Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…
A:
Q: A proton and an electron are moving due east in a constant electric field that also points due east.…
A: Magnitude of electric field, E= 7.0 x 104 N/C
Q: Problem 2: Space explorers discover an mA = 8.7 x 10¹7 kg asteroid that happens to have a positive…
A: The concept which will be used are given in the question. Find the complete solution in image…
Q: An electron has an initial velocity of 6.00 ✕ 106 m/s in a uniform 9.00 ✕ 105 N/C strength electric…
A:
Q: A particle of mass 0.000138 g and charge 81 mC moves in a region of space where the electric field…
A: From the question, it is given that- Mass of particle: m = 0.000138 g = 1.38 x 10-7 kg Charge on the…
Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…
A:
Q: An electron has an initial velocity of 8.00 x 10 m/s in a uniform 9.00 x 105 N/C strength electric…
A:
Q: Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of…
A: When a charged particle is in a electric field, it experiences a force on itself. This force,…
Q: At some instant the velocity components of an electron moving between two charged parallel plates…
A: As per our guidelines, we will solve only first question for you. To get remaining question solved…
Q: An electron with speed vo = 12.6 x 106 m/s is traveling parallel to a uniform electric field of…
A:
Q: An electron travels at a speed of 2.58.104 km/s parallel to an electric field of magnitude 1.20-104…
A:
Q: A particle (mass = 4.0 g, charge = 51 mC) moves along the x-axis in a region of space where the…
A: Data given , Mass of the particle ( m ) = 4 gm = 4 × 10-3 kg…
Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…
A: Force exerted on electron in cathode ray tube is electric field. Formula of electric field is as…
Q: The electric field at a point in space is E = (700 I +600 J). What is the magnitude of the electrons…
A: Given that, Electric field, E = 700i + 600j We know that charge of electron and proton is, Q = 1.6…
Q: A proton has an initial velocity of 3.7 × 107 m/s in the horizontal direction. It enters a uniform…
A: Given data The initial velocity of the proton is given as v = 3.7 x 107 m/s. The electric field is…
Q: An electron has an initial velocity of 6.00 ✕ 106 m/s in a uniform 9.00 ✕ 105 N/C strength electric…
A: Given data: The initial velocity, v=6.00×106 m/s The electric field E= 9.00×105 N/C
Q: An electron is released from rest in a uniform electric field. The electron accelerates vertically…
A:
Q: A proton is fired horizontally into a 1.0 × 105 N/C vertical electric field. It rises 1.0 cm…
A:
Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…
A: Given data The magnitude of the electric field is given as E = 315 N/C. The time interval is given…
Q: nside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of…
A: Given: The strength of the electric field is 285 N/C. The initial speed of the electron is 0 m/s.…
Q: An electron, starting from rest, is accelerated by a uniform electric field of 9.00 × 104 N/C that…
A: Please see the attached image for the solution.If there are queries or if the image is not loading,…
Q: An electron has an initial velocity of 10.0 x 106 m/s in a uniform 3.00 x 105 N/C strength electric…
A:
Q: The electric field is zero everywhere except in the region 0≤x≤4.00 cm, where there is a uniform…
A: Magnitude of electric field E = 110 N/C Speed of proton v = 1.00×106 m/s. Region of electric field E…
Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…
A: (a) Acceleration, a = Force / Mass of electron Force of an electron, F = eE Thus, a = eE / m a =…
Q: An electron is placed in a uniform electric field of E = (3.24 x 10e3 N/C) i + (1.35 x 10e3 N/C) j .…
A:
![A particle of mass m = 1.0 mg and charge 2.0 µC is placed in a region of space that has a constant
electric field of magnitude 2000 N/C. What is the magnitude of the acceleration of the particle?
1 m/s?
4 m/s?
9.8 m/s?
O 2000 m/s?
4000 m/s?
O 4 x 10° m/s?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5ca7e877-8b51-4055-848b-82d9a76b3c01%2F790abf81-2a75-463c-8372-1cc478632a35%2Fjr04q4i_processed.png&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
- Problem 13: An electron has an initial velocity of 5.15 × 106 m/s in a uniform 1.9 × 105 N/C electric field. The field accelerates the electron in the direction opposite to its initial velocity. Part A: How far does the electron travel before coming to rest in m? Part B: How long does it take the electron to come to rest in s? Part C: What is the magnitude of the electron's velocity (in m/s) when it returns to its starting point in the opposite direction of its initial velocity?An electron (m 9.11x10 31 kg) accelerates in a uniform electric field E = 1.45 x 10 N/C. What is the acceleration of the electron after it traveled 10 cm in the electric field? O A. 2.55 x 1014 m/s² O B. 2.55 x 1015 m/s? C. 1.5 x 1014 m/s? O D. 1.5 x 1015 m/s² O E. None Nex to searchA horizontal electron beam consists of electrons moving at 2000 m/s through two parallel, horizontal plates that are 0.01 m long and generate a uniform and constant 0.5 N/C electric field that points upward. What is the vertical component of the electron's velocity upon exiting the field in m/s? Assume the plate separation is sufficient that you do not need to worry about the electrons hitting the plate.
- Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a magnitude of 325 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s²)? m/s² (b) The electron is initially at rest. What is its speed (in m/s) after 1.05 x 10-8 s? m/sInside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 275 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s )? Im/s" (b) The electron is initially at rest What is its speed (in m/s) after 1.25 x 10 s? m/s 2 95A particle of mass m = 1.0 g and charge 2.0 µC is placed in a region of space that has a constant electric field of magnitude 2000 N/C. What is the magnitude of the force exerted on the particle due to the electric field? O 4 x 103 N O 2N O 4N O 1000 N 2000 N O 4000 N 2 x 10° N O 1x 10° N
- Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 293 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s²)? m/s² 4.0 (b) The electron is initially at rest. What is its speed (in m/s) after 1.05 x 10-8 s? 4.0 m/sAn electron is traveling through a uniform electric field. The field is constant and given by E=(2.00×10−11N/C) i^− (1.20×10−11N/C) j^. At t=0 , the electron is at the origin and traveling in the x direction with a speed of 2.20 m/s. Part A) What is its position 2.50 s later? x= ? (in m) Part B) y=?In this example, we will analyze the motion of an electron that is released in an electric field. The terminals of a 100 V battery are connected to two large, parallel, horizontal plates 1.0 cm apart. The resulting charges on the plates produce an electric field E in the region between the plates that is very nearly uniform and has magnitude E = 3.0×104 N/C. Suppose the lower plate has positive charge, so that the electric field is vertically upward, as shown in (Figure 1). (The thin pink arrows represent the electric field.) If an electron is released from rest at the upper plate, what is its speed just before it reaches the lower plate? How much time is required for it to reach the lower plate? The mass of an electron is mẹ = 9.11 x 10-31 kg. The thin arrows represent the uniform electric field. 1.0 cm 100 V In this example, suppose a proton (mp = 1.67 × 10-27 kg) is released from rest at the positive plate. What is its speed just before it reaches the negative plate? Express your…
- An electron is moving horizontally at 3 x 10^6 m/s when it enters an electric field. If the electron deflects 0.9 cm downward in a distance of 2.5 cm determine the magnitude and direction of the electric field.Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a magnitude of 275 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s2)? m/s2 (b) The electron is initially at rest. What is its speed (in m/s) after 1.20 ✕ 10−8 s? m/sAn electron is released from rest in a uniform electric field. If the electric field is 1.25 kN/C, at the end of 20 ns the electron's velocity will be approximately Group of answer choices 3.9 × 103 m/s. 4.4 × 106 m/s. 2.5 × 103 m/s. 3.0 × 108 m/s. 2.5 × 10–5 m/s.