An electron travels at a speed of 2.58.104 km/s parallel to an electric field of magnitude 1.20-104 N/C. What distance will the electron travel before coming to a stop? O 11.5 cm 14.0 cm 31.6 cm 15.8 cm 23.0 cm
An electron travels at a speed of 2.58.104 km/s parallel to an electric field of magnitude 1.20-104 N/C. What distance will the electron travel before coming to a stop? O 11.5 cm 14.0 cm 31.6 cm 15.8 cm 23.0 cm
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Physics Problem: Electron Dynamics in an Electric Field**
---
### Problem Statement:
An electron travels at a speed of \(2.58 \times 10^4 \) km/s parallel to an electric field of magnitude \(1.20 \times 10^4 \) N/C. What distance will the electron travel before coming to a stop?
### Multiple Choice Options:
- \(11.5 \, \text{cm}\)
- \(14.0 \, \text{cm}\)
- \(31.6 \, \text{cm}\)
- \(15.8 \, \text{cm}\)
- \(23.0 \, \text{cm}\)
**Explanation:**
In this problem, you are required to determine the distance an electron will travel before it comes to a stop when it is subjected to a specific electric field.
---
To solve this, consider the following key concepts:
1. **Kinematics and Dynamics of Electrons in an Electric Field:**
- The electron will experience a constant deceleration due to the electric field.
- The force acting on the electron can be calculated using Coulomb's law: \( F = q \times E \)
2. **Kinetic Equations:**
- You can use the equations of motion to find the distance traveled by the electron under constant deceleration until its velocity becomes zero.
**Note to Students:** Be sure to convert units appropriately (e.g., from km/s to m/s) and understand the relationship between the distance, electric field strength, and electron charge.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67028db1-3c15-42d7-aa43-8659f6c3f0f2%2F557191b5-340b-4116-9132-1dcff67a1028%2Fd39u7bf_processed.png&w=3840&q=75)
Transcribed Image Text:**Physics Problem: Electron Dynamics in an Electric Field**
---
### Problem Statement:
An electron travels at a speed of \(2.58 \times 10^4 \) km/s parallel to an electric field of magnitude \(1.20 \times 10^4 \) N/C. What distance will the electron travel before coming to a stop?
### Multiple Choice Options:
- \(11.5 \, \text{cm}\)
- \(14.0 \, \text{cm}\)
- \(31.6 \, \text{cm}\)
- \(15.8 \, \text{cm}\)
- \(23.0 \, \text{cm}\)
**Explanation:**
In this problem, you are required to determine the distance an electron will travel before it comes to a stop when it is subjected to a specific electric field.
---
To solve this, consider the following key concepts:
1. **Kinematics and Dynamics of Electrons in an Electric Field:**
- The electron will experience a constant deceleration due to the electric field.
- The force acting on the electron can be calculated using Coulomb's law: \( F = q \times E \)
2. **Kinetic Equations:**
- You can use the equations of motion to find the distance traveled by the electron under constant deceleration until its velocity becomes zero.
**Note to Students:** Be sure to convert units appropriately (e.g., from km/s to m/s) and understand the relationship between the distance, electric field strength, and electron charge.
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