Some forms of cancer can be treated using proton therapy in which proton beams are accelerated to high energies, then directed tocollide into a tumor, killing the malignant cells. Suppose a proton accelerator is 4.80 m long and must accelerate protons from rest to aspeed of 2.00 × 10' m/s. Ignore any relativistic effects and determine the magnitude of the average electric field that could acceleratethese protons. Mass of proton is 1.673 x 10-27 kg and charge of proton is 1.602 × 10-19C.N/C

Write the equation of kinematics to calculate the acceleration of the proton.…

Answered: Some forms of cancer can be treated…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Suppose an electron (q = -e = -1.6 x 10¬9 C,m=9.1 x 10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for %3D the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U 1 Since K mv and using the formula for potential energy above, we arrive at an equation for speed: 2 v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=
The Russian physicist P. A. C˘ erenkov discovered that a charged particle traveling in a solid with a speed exceeding the speed of light in that material radiates electromagnetic radiation. (This is analogous to the sonic boom produced by an aircraft moving faster than the speed of sound in air; see Section 16.9. C˘ erenkov shared the 1958 Nobel Prize for this discovery.) What is the minimum kinetic energy (in electron volts) that an electron must have while traveling inside a slab of crown glass (n = 1.52) in order to create this C˘ erenkov radiation?
In a typical television or in an older computer monitor's cathode ray tube (CRT), electrons are accelerated from rest through a potential difference of 2.5×104 V, steered by magnetic fields, and finally strike particular spots on the screen at the front of the tube to create an image. What is the kinetic energy of the electrons after the accelerating process, as they are moving toward the screen?
How much total energy is needed to bring two protons within 5.75 fm of one another? Answer in femtojoules. 1 fm (femtometer) = 10^-15 m
A proton (m=1.67 x 10^-27 kg) travels a distance of 4.3 cm parallel to a uniform electric field 3.5 x 10^5 V/m between the plates shown in the figure. If the initial velocity is 3.2 x 10^5 m/s, find the magnitude of its final velocity in m/s. (Ignore gravity)
Please see attached question
What is the strength of the magnetic field at the center of a circular loop of wire of diameter 9.48 cm when a current of 5.91 A flows in the wire? (μ0 = 4π × 10-7 T ∙ m/A) (Use π = 3.14). Express answers in milliTeslas.
A constant electric field accelerates a proton from rest through a distance of 2.15 m to a speed of 1.49 ✕ 105 m/s. (The mass and charge of a proton are mp = 1.67 ✕ 10−27 kg and qp = e = 1.60 ✕ 10−19 C. (a)Find the change in the proton's kinetic energy (in J). (b)Find the change in the system's electric potential energy (in J). (c)Calculate the magnitude of the electric field (in N/C).
(a) Find the potential difference DVe required to stop an electron (called a “stopping potential”) moving with an initial speed of 2.85 × 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Δ Vp /Δ Ve . The answer should be in terms of the proton mass mp and electron mass me
What is the speed of an electron after being accelerated from rest through a 2.5×107 V potential difference? Express your answer as a fraction of cc.
If electrons have kinetic energy of 2000 eV, find (a) their speed, (b) the time needed to traverse a distance of 5 cm between plates that our horizontal, and (c) the vertical component of their velocity after passing between the plates if the electric field is 3.33 x 10^3 V/m.
(a) Calculate the speed of a proton that is accelerated from rest through a potential difference of 133 V.km/s(b) Calculate the speed of an electron that is accelerated through the same potential difference.Mm/s

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