The velocity of a parachutist as a function of time is given by v = vf + (v0 - vf)e-t/2.5, where t = 0 s corresponds to the instant the parachute is opened, v0 = 160 km/h is the velocity before opening of the parachute, and vf = 18 km/h is the final (terminal) velocity. What acceleration does the parachutist experience just after opening the parachute? (m/s^2)

The velocity of a parachutist as a function of time is given by v = vf + (v0 - vf)e-t/2.5, where t = 0 s corresponds to the instant the parachute is opened, v0 = 160 km/h is the velocity before opening of the parachute, and vf = 18 km/h is the final (terminal) velocity. What acceleration does the parachutist experience just after opening the parachute? (m/s^2)

Name: The velocity of a parachutist as a function of time is given by v = vf
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Description: The velocity of a parachutist as a function of time is given by v = vf + (v0 - vf)e-t/2.5, where t = 0 s corresponds to the instant the parachute is opened, v0 = 160 km/h is the velocity before opening of the parachute, and vf = 18 km/h is the final

Principles of Physics: A Calculus-Based Text

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ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

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