The vector position of a particle varies in time according to the expression $\vec{r} = 6.20 \hat{\imath} - 6.60t^2 \hat{\jmath}$ where $\vec{r}$ is in meters and $t$ is in seconds.(a) Find an expression for the velocity of the particle as a function of time. (Use any variable or symbol stated above as necessary.)\[\vec{v} = \boxed{} \quad \text{m/s}\]❌(b) Determine the acceleration of the particle as a function of time. (Use any variable or symbol stated above as necessary.)\[\vec{a} = \boxed{} \quad \text{m/s}^2\]❌(c) Calculate the particle's position and velocity at $t = 5.00 \, \text{s}$.\[\vec{r} = \boxed{} \quad \text{m}\]❌\[\vec{v} = \boxed{} \quad \text{m/s}\]❌Need Help?[Read It] [Watch It]

The rate of change of displacement is known as velocity. Velocity is given as: v→=ds→dt Here, s is…

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