The vector a can be projected onto the subspace spanned by uj and 02. This resulting projection of ā the closest element of the subspace spanned by the two vectors v1 and 72. We know that any element of a subspace is a linear combination of the basis, so projā = c1ū1 + c2Ū2 What is c1 given –1 18 20 and i2 = 19 11 Round you answer to two decimal places, i.e. –0.43

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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The vector à can be projected onto the subspace spanned by ởj
and 02. This resulting projection of ā the closest element of the
subspace spanned by the two vectors vj and 02. We know that
any element of a subspace is a linear combination of the basis, so
projā = c1ū1 + c2®2
What is c1 given
-1
18
20
2
and i2 =
-19
11
5
-4
Round you answer to two decimal places, i.e. -0.43
Transcribed Image Text:The vector à can be projected onto the subspace spanned by ởj and 02. This resulting projection of ā the closest element of the subspace spanned by the two vectors vj and 02. We know that any element of a subspace is a linear combination of the basis, so projā = c1ū1 + c2®2 What is c1 given -1 18 20 2 and i2 = -19 11 5 -4 Round you answer to two decimal places, i.e. -0.43
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