The various component weights for the three-wheeler are tabulated below and their center of gravity locations are shown in the figure. (note: each rear wheel weighs 9 pounds) A) Locate the center of gravity with respect to both the x and y axes for the three-wheeler shown. B) Assuming the three-wheeler is symmetrical about the x-y plane, determine the normal reaction each of its wheels exerts on the ground.

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I am trying to solve this one not with the weight, but rather the formula that uses sum of areas * centroid all over sum of areas... How is that possible?

Problem 14.2
The various component weights for the three-wheeler are tabulated below and their center of
gravity locations are shown in the figure. (note: each rear wheel weighs 9 pounds)
A) Locate the center of gravity with respect to both the x and y axes for the three-wheeler
shown.
B) Assuming the three-wheeler is symmetrical about the x-y plane, determine the normal
reaction each of its wheels exerts on the ground.
1. Rear wheels
2. Mechanical components 85 lb
3. Frame
4. Front wheel
18 lb
120 lb
8 lb
1 ft
1.50 ft 2 ft
1.30 ft
A
B
-2.30 ft-
- 1.40 ft -
0.80 ft
Transcribed Image Text:Problem 14.2 The various component weights for the three-wheeler are tabulated below and their center of gravity locations are shown in the figure. (note: each rear wheel weighs 9 pounds) A) Locate the center of gravity with respect to both the x and y axes for the three-wheeler shown. B) Assuming the three-wheeler is symmetrical about the x-y plane, determine the normal reaction each of its wheels exerts on the ground. 1. Rear wheels 2. Mechanical components 85 lb 3. Frame 4. Front wheel 18 lb 120 lb 8 lb 1 ft 1.50 ft 2 ft 1.30 ft A B -2.30 ft- - 1.40 ft - 0.80 ft
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